I need help with the hypotheses testing.

Mathematics

1 answer:

pentagon [3]3 years ago

6 0

Answer:

Hi hows life going?

Step-by-step explanation:

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F(X) = 3X – 4 THE DOMAIN FOR THE FUNCTION IS {1, 2, 3} WHAT IS THE RANGE?

Juliette [100K]

Answer:

y = {-1, 2, 5}

although, I am not sure how you want to format your answer

Step-by-step explanation:

just input the values for the domain

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2 years ago

Show your work. -2.5(4x -4) = -6

serg [7]

Answer:

x = 1 3/5

Step-by-step explanation:

distribute.

-2.5*4x + (-2.5*-4) = -6

-10x +10 = -6

subtract 10 on both sides

-10x = -6 -10

divide by -10

x = -16/-10

x = 1 3/5

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2 years ago

Segment AE is congruent to segment EB

Rudiy27

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3 years ago

Let C = C1 + C2 where C1 is the quarter circle x^2+y^2=4, z=0,from (0,2,0) to (2,0,0), and where C2 is the line segment from (2,

trapecia [35]

Not much can be done without knowing what $\mathbf F(x,y,z)$ is, but at the least we can set up the integral.

First parameterize the pieces of the contour:

$C_1:\mathbf r_1(t_1)=(2\sin t_1,2\cos t_1,0)$
$C_2:\mathbf r_2(t_2)=(1-t_2)(2,0,0)+t_2(3,3,3)=(2+t_2, 3t_2, 3t_2)$

where $0\le t_1\le\dfrac\pi2$ and $0\le t_2\le1$ . You have

$\mathrm d\mathbf r_1=(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1$
$\mathrm d\mathbf r_2=(1,3,3)\,\mathrm dt_2$

and so the work is given by the integral

$\displaystyle\int_C\mathbf F(x,y,z)\cdot\mathrm d\mathbf r$
$=\displaystyle\int_0^{\pi/2}\mathbf F(2\sin t_1,2\cos t_1,0)\cdot(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1$
${}\displaystyle\,\,\,\,\,\,\,\,+\int_0^1\mathbf F(2+t_2,3t_2,3t_2)\cdot(1,3,3)\,\mathrm dt_2$