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Cloud [144]
2 years ago
7

Can anyone help me with this

Mathematics
1 answer:
belka [17]2 years ago
4 0

Answer:

  47.2°

Step-by-step explanation:

Triangles PRQ and SRQ are congruent by HL. In these right triangles, the acute angles are complementary.

angle PRQ  = angle SRQ = 90° -42.8° = 47.2°

The measure of angle PRQ is 47.2°.

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A retailer at an outdoor market sold 5 dresses at $36.95 each. He sold 2 more at $41.99 each and 3 at $38.95 each. He also sold
ss7ja [257]
5*36.95= $<span>184.75
2*42.99= $</span><span>85.98
3*38.95= $</span>116.85
1*52*0.6=$<span>31.20    (40% off) multiply by 0.6)

Add 184.75+85.98+116.85+31.20=$</span>418.78 - 20% thus: 418.78*.8= $ <span>335.024</span>
6 0
3 years ago
Read 2 more answers
ANSWER IF UR SURE 11 Points <br> ANSWER 6 &amp; 7
Zepler [3.9K]

6) answer is B , random sampling produces a representative sample


7)  0.1 = 10% so the answer is A, he saves 10% of his income

4 0
3 years ago
8 3/5 = -4x + 5 3/5 ??<br> Solution??
olasank [31]

Answer:

x=−3/4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

435=−4x+285

Step 2: Flip the equation.

−4x+285=435

Step 3: Subtract 28/5 from both sides.

−4x+285−285=435−285

−4x=3

Step 4: Divide both sides by -4.

−4x−4=3−4

x=−34

6 0
3 years ago
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What is the solution to the equation below? Round your answer to two
tester [92]

Answer:

Answer:.1.77

Step-by-step explanation:

e^x = 5.9

Take the natural logarithm of both sides

x = ln (59/10)

x = 1.77

(found this)

3 0
3 years ago
Find the perimeter of the quadrilateral.
levacccp [35]

<em><u>Question:</u></em>

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

The complete figure of this question is attached below

<em><u>Answer:</u></em>

<h3>The perimeter of the quadrilateral is 129 inches</h3>

<em><u>Solution:</u></em>

The complete figure of this question is attached below

Given that, a quadrilateral with,

Side lengths are:

4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches

The values of the side lengths when x = 2 are

(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch

Perimeter of a quadrilateral = Sum of its sides

Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches

Thus perimeter of the quadrilateral is 129 inches

5 0
3 years ago
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