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2 years ago

6

Sadie bought 4 packages of napkins and 2 packages of cups. which item had more in each package? how many more?

1 answer:

saw5 [17]2 years ago

8 0

To determine the number of items in each of the packages, we simply multiply the number of packages and the number of items in each package.

(1) For the 4 packages of napkin.

(4 packages)(28 napkins/package) = 112 napkin

(2) For 2 packages of cups

(2 packages)(24 cups/package) = 48 cups

From the calculated values, it may be concluded that 4 packages of napkin will have more number of items.

b. By how much?

D = 112 - 48 = 64

<em>Answer: 64</em>

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valentinak56 [21]

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504

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3 years ago

Use the definition of the derivative to differentiate v=4/2 pie r^3

nata0808 [166]

I suspect 4/2 should actually be 4/3, since 4/2 = 2, while 4/3 would make V the volume of a sphere with radius r. But I'll stick with what's given:

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2 years ago

Which of the following theorems verifies that ABC~WXY?

Bumek [7]

Answer:

The correct answer is option <em>B. AA</em>

<em></em>

Step-by-step explanation:

Given two triangle:

$\triangle ABC$ and $\triangle WXY$ .

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$\angle A = 27^\circ\\\angle B = 90^\circ$

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$\angle A+\angle B+\angle C = 180^\circ\\\Rightarrow 27+90+\angle C=180^\circ\\\Rightarrow \angle C = 63^\circ$

The dimensions given in $\triangle WXY$ are:

$\angle Y = 63^\circ\\\angle X = 90^\circ$

We know that the sum of three angles in a triangle is equal to $180^\circ$ .

$\angle W+\angle X+\angle Y = 180^\circ\\\Rightarrow \angle W+90+63=180^\circ\\\Rightarrow \angle W = 27^\circ$

Now, if we compare the angles of the two triangles:

$\angle A = \angle W = 27^\circ\\\angle B = \angle X= 90^\circ\\\angle C = \angle Y= 63^\circ$

So, by AA postulate (i.e. Angle - Angle) postulate, the two triangles are similar.

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2 years ago

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3 years ago