Some applications required advanced storage solutions are available to provide fault tolerance and high performance.
1 answer:
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Answer:
Check the explanation
Explanation:
CODE:-
import java.util.ArrayList;
class Student
{
private String name;
private int grade;
private static ArrayList<Student> classList = new ArrayList<Student>();
public Student(String name, int grade)
{
this.name = name;
this.grade = grade;
classList.add(this);
}
public String getName()
{
return this.name;
}
/*Don't change the code in this method!
This method will print out all the Student names in the classList Array
*/
public static String printClassList()
{
String names = "";
for(Student name: classList)
{
names+= name.getName() + "\n";
}
return "Student Class List:\n" + names;
}
}
public class ClassListTester
{
public static void main(String[] args)
{
//You don't need to change anything here, but feel free to add more Students!
Student alan = new Student("Alan", 11);
Student kevin = new Student("Kevin", 10);
Student annie = new Student("Annie", 12);
Student smith = new Student("Smith", 11);
Student kane = new Student("Kane", 10);
Student virat = new Student("Virat", 12);
Student abd = new Student("ABD", 12);
Student root = new Student("Root", 12);
System.out.println(Student.printClassList());
}
}
Kindly check the attached image below.
