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Sonbull [250]
3 years ago
14

HELP ME PLEASE

Computers and Technology
1 answer:
seraphim [82]3 years ago
3 0

Answer:

Questions and answers

Explanation:

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Which of the following calculates to 19<br>(3*6)+2/2<br>3*(6+2)/2<br>(3*6+2)/2<br>3*(6+2/2)​
Firdavs [7]

Answer: The first one (3*6)+2/2 will equal 19.

Explanation: If you use the order of operation you would do 3*6 first then add that to 2/2. So it would be 18+1=19.

3 0
3 years ago
What process does a system use to officially permit access to a file or a program CIS 502 ?
ipn [44]

Answer:

Authorization                                

Explanation:

Authorization is a security process to determine access levels related to system resources such as files, services, computer programs, data and application features. This is the method of allowing or denying access to a resource which enables the user to get access to various services and resources depending on the user's identity.

Authorization is the process that checks if a user has the permission to get access to a particular file or perform a particular action, ensuring that user has successfully authenticated himself. It refers to defining access policy.

For example a system administrator determines for the system device, in multi-user computer systems, which users are granted access to system and its resources and privileges are granted.

4 0
3 years ago
Write a test client for Randomthat checks that two methods, namely, nextGaussian()and nextLong()in the library operate as expect
xenn [34]

Answer:

/ TestRandom.java

import java.util.Random;

public class TestRandom {

   // method to find the mean value of set of numbers

   // using Number as data type, so that it can represent both Double and Long

   // types needed for this program

   static double calculateMean(Number array[]) {

        double sum = 0;

        // summing values

        for (int i = 0; i < array.length; i++) {

            sum += array[i].doubleValue();

        }

        // finding average and returning it

        double avg = (double) sum / array.length;

        return avg;

   }

   // method to find the standard deviation value of set of numbers

   // using Number as data type, so that it can represent both Double and Long

   // types needed for this program

   static double calculateSD(Number array[], double mean) {

        // initializing sum of squared difference between each number and mean

        // to 0

        double sumSquaredDiff = 0;

        // looping

        for (int i = 0; i < array.length; i++) {

            // finding difference between current number and mean, squaring the

            // result, adding to sumSquaredDiff

            sumSquaredDiff += Math.pow(array[i].doubleValue() - mean, 2);

        }

        // finding variance

        double variance = (double) sumSquaredDiff / array.length;

        // finding square root of variance as standard deviation

        double sd = Math.sqrt(variance);

        return sd;

   }

   public static void main(String[] args) {

        // if no command line arguments given, displaying usage and quit

        if (args.length == 0) {

            System.out.println("Usage: java TestRandom <n>");

            System.exit(0);

        }

        // parsing first argument as integer N

        int N = Integer.parseInt(args[0]);

        // declaring a Double array and a Long array of size N

        Double gaussian[] = new Double[N];

        Long lng[] = new Long[N];

        // Random number generator

        Random random = new Random();

        // looping for N times

        for (int i = 0; i < N; i++) {

            // generating a guassian number, adding to array

            gaussian[i] = random.nextGaussian();

            // generating a long number, adding to array

            lng[i] = random.nextLong();

        }

        // finding average and standard deviation of both array values, we can

        // use the same functions for both types

        double avgGaussian = calculateMean(gaussian);

        double sdGaussian = calculateSD(gaussian, avgGaussian);

        double avgLong = calculateMean(lng);

        double sdLong = calculateSD(lng, avgLong);

        // displaying mean and standard deviation of both, formatted to 2 digits

        // after decimal point. the gaussian values will yeild a mean value

        // close to 0 and a standard deviation close to 1

        System.out.printf("Mean of %d gaussian values: %.2f\n", N, avgGaussian);

        System.out.printf("Standard deviation: %.2f\n", sdGaussian);

        System.out.printf("Mean of %d long values: %.2f\n", N, avgLong);

        System.out.printf("Standard deviation: %.2f\n", sdLong);

   }

}

Explanation:

5 0
3 years ago
The Euclidean algorithm - The Euclidean algorithm provides a wonderful way to calculate the greatest common factor of 2 numbers.
Murljashka [212]

The pseudo-code of the algorithm will be:

Start

Set n1 equal to 145 and n2 equal to 87.

Divide n1 by n2 and find the remainder.

Set n1 equal to n2 and n2 equal to the remainder.

Repeat steps 2 and 3 until the remainder is equal to 0.

The greatest common factor is n1.

End

What do you mean by pseudocode?

In computer science, pseudocode is indeed a plain language description of a steps in an algorithm or similar system. Pseudocode frequently employs structural patterns of a conventional programming language, although it is designed for human interpretation rather than machine reading. It generally omits features necessary for computation of the algorithm, including such variable declarations and language-specific code. When possible, the programming language is supplemented by natural language description details or succinct mathematical notation.

To learn more about pseudocode

brainly.com/question/24735155

#SPJ9

4 0
1 year ago
When a cellular telephone user places a call, the carrier transmits the caller’s voice as well as the voice of the person who is
slava [35]
To estimate the number of phone calls that will be placed net monday between 10:30 AM and noon and to generate a list of criminal suspects when given the telephone number of a known criminal
4 0
3 years ago
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