It will just keep going on as a decimal so you do not need to keep going, three spaces after the decimal should be an acceptable answer.
Dice A has the sides 2, 2, 4, 4, 6, 6 and Dice B has 1, 3, 1, 3, 1, 3. What is the probability that when you roll the dice Dice
aleksandr82 [10.1K]
Answer:
i remember doing a question just like this. Im pretty sure the answer is 1/4
Step-by-step explanation:
1. Start with ΔCIJ.
- ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
- the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
- ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.
2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So
m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.
3. Consider ΔCKL.
- ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
- ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
- the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
- ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.
4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So
m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.
5. ΔABC is isosceles, then angles adjacent to the base are congruent:
m∠KBA=m∠JAB → 222°-8x=205°-7x,
7x-8x=205°-222°,
-x=-17°,
x=17°.
Then m∠CAB=m∠CBA=205°-7x=86°.
Answer: 86°.
Answer:
I jumps 1 every time
Step-by-step explanation: Say you start at 6 and you have to get to 8 you add 2 to get to 8 if you want to get to 11 you would add 3.
the only thing you need to do is separate m:
2/7m= 3/14 + 1/7
2/7m= 5/14
m= (5/14)/(2/7)
m= 5/14 × 7/2
m= 35/28
m= 5/4
