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Paul [167]
3 years ago
15

The price of a skateboard after a 25% discount is $165. What was the price before the discount?

Mathematics
2 answers:
tekilochka [14]3 years ago
8 0

Answer: this is an example

If you knew the original value then you would multiply by 1.10 to calculate the price after markup. Thus if you know the price after markup you divide by 1.10 to find the original value. Hence if the price after markup is $27.50 then the original price was $27.50/1.10 = $25.00.

Step-by-step explanation:

Fantom [35]3 years ago
8 0
25% of 660 is 165- so the skateboard was $660 before the discount (i believe so)
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Put these decimals in order starting with the smallest.
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zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

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3 years ago
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