Answer:
a. z = 2.00
Step-by-step explanation:
Hello!
The study variable is "Points per game of a high school team"
The hypothesis is that the average score per game is greater than before, so the parameter to test is the population mean (μ)
The hypothesis is:
H₀: μ ≤ 99
H₁: μ > 99
α: 0.01
There is no information about the variable distribution, I'll apply the Central Limit Theorem and approximate the sample mean (X[bar]) to normal since whether you use a Z or t-test, you need your variable to be at least approximately normal. Considering the sample size (n=36) I'd rather use a Z-test than a t-test.
The statistic value under the null hypothesis is:
Z= X[bar] - μ = 101 - 99 = 2
σ/√n 6/√36
I don't have σ, but since this is an approximation I can use the value of S instead.
I hope it helps!
Total area = 9 x5 =45
Total area = (6+3)(4+1)=24+6+12+3=45
Answer:
μ = 1 The firm expects that one oil exploration will be successful.
v(x)= 0.9
Step-by-step explanation:
The first step is to define the random variable x as:
x: number of oil explorations being succesful
Then x can be take this values:
x = 0 , x =1 ... x =10
x is a binomially distributed random variable with parameters.
p = 0.1 and n=10
And the mean or the expected value of x is:
μ = E(x) = np
Then μ = 10*0.1 = 1
And the variance of x is:
V(x) = np(1-p)
V(x) = 10(0.1)(1-0.1)= 0.9
Answer: 3 games
Step-by-step explanation:
10.5
First subtract 3 because you will need shoes.
7.50
Now divide by 2.50
7.5/2.5
3 GAMES
4x (4 peaches) = 4y (4.96$)
x (4/4 peaches=1) = y (4.96$ / 4 = 1.24$)
y f(x) = 1.24$
