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erastova [34]
3 years ago
14

If f(x)=(x-3)^2+1 what is f(6) Pls help

Mathematics
1 answer:
lyudmila [28]3 years ago
8 0

Answer:

I love algebra anyways  

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

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A car travels at 49 km/hour how far does it travel in a 12 hour day​
marta [7]

Answer:   2.88 km.

Step-by-step explanation:

We will discuss here how to find the distance when speed and time are given.

When speed and time are given, the distance travelled is calculated by using the formula:

Distance = Speed × Time

The unit of time in speed should be the same as that of the given time.

Solved examples to calculate distance when speed and time are given:

1. How much distance will be covered in 5 hrs at a speed of 55 km per hour?

Solution:

Distance covered in 1 hour = 55 km.

We know, Distance = Speed × Time

Distance covered in 5 hrs = 55 × 5

                                  = 275 km.

Therefore, distance covered in 5 hrs = 275 km.

2. A bus travels at a speed of 45 km/hour. How far will it travel in 36 minutes?

Solution:

Speed = 45 km/hour

Time = 36 minutes

      = 36/60 Hour (Since we know, 1 hour = 60 minutes)

      = 3/5 hour

Distance = speed × time

           = 45 × (3/5) km

           = (45 × 3)/5 km

           = 27 km.

3. How much distance will be covered in 7 hrs at a speed of 62 km per hour?

Solution:

Distance covered in 1 hour = 62 km.

We know, Distance = Speed × Time

Distance covered in 7 hrs = 62 × 7

                                     = 434 km.

Therefore, distance covered in 7 hrs = 434 km.

4. Mike drives his car at a speed of 70 km per hour. How much distance will he cover in 3 hours 30 minutes?

Solution:

Speed of the car = 70 km/hr

Time taken         = 3 hours 30 minutes

                        = 3 ½ hours.

Distance covered in 1 hour = 70 km

Distance covered in 3 ½ hour = 70 × 3 ½ km

                                          = 70 × 7/2 km

                                          = 245 km.

5. How much distance will be covered in 1 ½ hour at a speed of 32 m per minute?

Solution:

[1 ½ hr = (60 + 30) minutes = 90 minutes].

Distance covered in 1 minute = 32 metres.

Distance covered in 90 minutes = 32 × 90 = 2880 m.

We know, 1 m = 1/1000 km.

                     = 2880/1000 km.

                     = 2.88 km.

Hope this helps!

5 0
2 years ago
What is the length of the apothem, rounded to the nearest inch? recall that in a regular hexagon, the length of the radius is eq
NNADVOKAT [17]

Answer:

Step-by-step explanation:

What is the length of the apothem, rounded to the nearest inch? recall that in a regular hexagon, the length of the radius is equal to the length of each side of the hexagon. 4 in. 5 in. 9 in. 11 in.

8 0
2 years ago
Read 2 more answers
Not the best pic but I think it’s still readable.. pls answer for all.. thanks
luda_lava [24]

Answer:

a) y=5ˣ-3

b) y=5ˣ⁻²

c) y=5^(x+1/2)

d) y=5^(x+2.5)+1

Step-by-step explanation:

y=b*5^{ax-h}+k

b: vertical stretch or compression and reflection across x-axis

a: horizontal stretch or compression and reflection across y-axis

h: horizontal shift (left and right)

k: vertical shift (up and down)

a) y=5ˣ-3

b) y=5ˣ⁻²

c) y=5^(x+1/2)

d) y=5^(x+2.5)+1

5 0
3 years ago
Need help <br> Correct answers only.
disa [49]

The diameter of the circle is the same as the side length of the bounding square. The radius of the circle is 8 in, so the side length of the square is 16 in.

Then the area between the square and circle is obtained by subtracting the area of the circle from the area of the square:

A_{\rm circle}=\pi(8\,\mathrm{in})^2=64\pi\,\mathrm{in}^2

A_{\rm square}=(16\,\mathrm {in})^2=256\,\mathrm{in}^2

and the area you want is

256-64\pi\,\mathrm{in}^2\approx54.9\,\mathrm{in}^2

6 0
4 years ago
A book has a front and a back and 200 pages.
MariettaO [177]

Answer:

28.3mm

Step-by-step explanation:

upper bound of front and back cover=0.75mm and lower bound=0.65mm

lower bound of page=0.135mm and upper bound=0.145mm

As there is a front and back cover we multiply the lower bound by 2

as there is 200 pages we multiply the lower bound by 200

(0.65*2)+(0.135*200)=28.3mm

3 0
3 years ago
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