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Stels [109]
3 years ago
5

Plz, Help me with this!!!! Plz, Help me with this!!!!

Mathematics
2 answers:
Kazeer [188]3 years ago
6 0

Answer:

-3x-4

Step-by-step explanation:

first you add 5x and -8x to get -3x, then you get -4.

Maslowich3 years ago
3 0

Answer:

-3x+2

Step-by-step explanation:

Since it's addition you just combine all like terms so,

5x+4

-8x-2

= -3x+2

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Y=1/2x+2 since the slope is 1/2 and the y intercept is 2
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Find the sum of -2 + 3i and -1- 2i.
blondinia [14]

Answer:

-3+i

Step-by-step explanation:

Collect like terms

-2-1=-3

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7 0
2 years ago
Is square root 1 minus sine squared theta = cos Θ true? If so, in which quadrants does angle Θ terminate?
Cloud [144]

Answer:

True; quadrants I & IV

Step-by-step explanation:

We know the relation between sine and cosine function which is given by

\sin^2 \theta +\cos^2 \theta = 1

Let us solve this equation for cosine function.

\cos^2 \theta = 1-\sin^2 \theta

Take square root both sides. When ever we take square root we need to write the solution in plus minus form

\sqrt{\cos^2 \theta}=\pm\sqrt{1-\sin^2 \theta}

\cos \theta=\pm\sqrt{1-\sin^2 \theta}

\cos \theta=-\sqrt{1-\sin^2 \theta}, \sqrt{1-\sin^2 \theta}

If Θ is in quadrants I and IV then the value will be positive and if Θ is in II and III quadrant then the value is negative.

Hence, if Θ is in quadrants I & IV, then we have

\cos \theta=\sqrt{1-\sin^2 \theta}

Thus, the correct option is: True; quadrants I & IV


6 0
3 years ago
Read 2 more answers
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I hope this helps you

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