All categories

3 years ago

Plz, Help me with this!!!! Plz, Help me with this!!!!

Mathematics

2 answers:

Kazeer [188]3 years ago

6 0

Answer:

-3x-4

Step-by-step explanation:

first you add 5x and -8x to get -3x, then you get -4.

Maslowich3 years ago

3 0

Answer:

-3x+2

Step-by-step explanation:

Since it's addition you just combine all like terms so,

5x+4

-8x-2

= -3x+2

You might be interested in

Please help i’ll give brainliest

Furkat [3]

Answer:

The answer is A, a total of 12 students spend 31 or more hours online per month.

Step-by-step explanation:

From the hours of 31 to 65 there are twelve students.

7 0

3 years ago

The length L of a rectangle is 4 units more than its width W. The rectangle's are is 252 square units. A) Write the equation tha

jek_recluse [69]

Answer:

w=14

l=18

Step-by-step explanation:

To find the dimensions, create an equation for its area and solve for each using the area formula A = l*w. The dimensions given are A = 252, w for width and l= w+4 (4 more than the width).

$A = l*w\\252 = (w+4)*w\\252 = w^2+4w\\252+4 = w^2 +4w +4\\256 = (w+2)^2\\\sqrt{256} =\sqrt{(w+2)^2} \\16 = w+2\\16 = w+2\\14= w\\$

The width is 14 so the length is l=w+4 or l= (14)+4 =18

3 0

3 years ago

What is the definition of COEFFICIENT?

Lady_Fox [76]

Either the 4th answer or 1st one

5 0

3 years ago

Which transformations will alter the location of the vertex?

VashaNatasha [74]

Answer:

reflection

transition left / right are the location of the vertex

4 0

3 years ago

What is the ratio of the area of the inner square to the area of the outer square?

Anastasy [175]

Answer:

$\frac{(a-b)^2+b^2}{a^2}$

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

$=\sqrt{(a-b-0)^2+(0-b)^2}$

$=\sqrt{(a-b)^2+b^2}$

Thus the area of the inner square = (side)²

$=(\sqrt{(a-b)^2+b^2})^2$

$=(a-b)^2+b^2\text{ square cm}$

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

$=\sqrt{(a-0)^2+0^2}$

$=\sqrt{a^2}=a$

Thus, the area of the outer square = (side)²

$=a^2\text{ square cm}$

Hence, the ratio of the area of the inner square to the area of the outer square

$=\frac{(a-b)^2+b^2}{a^2}$

4 0

3 years ago

Read 2 more answers