All categories

3 years ago

8 7 / 8 + 9 13 / 16 what is this in a mixed number.

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

5 0

Answer:

18 and 11/16

Step-by-step explanation:

I converted the two numbers into improper fractions which leaves me with

71/8+157/16

I thenn made sure I had common denominators, which means I need to multiply the first number by 2/2 and I'm left with:

142/16+157/16

I can now add the 2 numbers together and I get:

299/16

now we just need to convert the number into a mixed number by dividing, and I am left with:

18 and 11/16

You might be interested in

What is the distance between -2 1/2,-3and 1,3

just olya [345]

Answer:

hbhggvv333 788.5

Step-by-step explanation:

3 0

3 years ago

Write a real world problem that compares 0.4 and 0.29. Then solve the problem

Ostrovityanka [42]

Bob found 2 types of ropes at a store. They were both the same price with one that is 0.4m and the other one is 0.29. Which one is the best deal? The best deal is obviously the 0.4m

7 0

4 years ago

Write a function g whose graph represents the

Klio2033 [76]

Answer:

eew3fe

Step-by-step explanation:

6 0

3 years ago

In aâ€‹ lottery, 6 numbers are randomly sampled without replacement from the integers 1 to 50. Their order of selection is not i

nlexa [21]

Answer: 0.444225

Step-by-step explanation:

Given : The total number of tickets = 50

Number of tickets are randomly sampled without replacement =6

Since the order of selection is not important , so we use combinations.

Total number of ways to select 6 tickets = $^{50}C_6$

The number of winning tickets = 6

So, number of tickets that are not winning = 50-6=44

Number of ways of selecting zero winning numbers= $^{44}C_{6}$

Now , the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket out of the 50 possible numbers would be $\dfrac{^{44}C_{6}}{^{50}C_6}$

$=\dfrac{\dfrac{44!}{6!(44-6)!}}{\dfrac{50!}{6!(50-6)!}}\\\\\\=\dfrac{\dfrac{44\times43\times42\times41\times40\times39\times38!}{38!}}{\dfrac{50\times49\times48\times47\times46\times45\times44!}{44!}}\\\\\\=\dfrac{44\times43\times42\times41\times40\times39}{50\times49\times48\times47\times46\times45}\\\\=\dfrac{252109}{567525}\approx0.444225$

Hence, the required probability = 0.444225

8 0

3 years ago

The local office supply store charges $0.08 per page to make photocopies. Lionel paid $20.00 for a set of copies. How many pages

Ivanshal [37]

Lionel had 250 pages copied

This is because 20/.08=250.

8 0

4 years ago

Read 2 more answers