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3 years ago

Help! Plz thank you!!!!

Mathematics

1 answer:

Brums [2.3K]3 years ago

6 0

Answer:

i do not see a picture or an image of what you need.

Step-by-step explanation:

You might be interested in

There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one

diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

$P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02$

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01$

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05$

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C$

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0

4 years ago

BRAINEST IF YOU GET THSI RIGHT

Scorpion4ik [409]

<h3>Solution :</h3>

$\sf \dfrac{6x+4}{3} = \dfrac{5x-5}{8}$

By cross multiply, we get

$\sf : \implies (6x+4) \times 8 = (5x-5) \times 3$

$\sf : \implies 48x+32 = 15x-15$

$\sf : \implies 48x+32 - 15x + 15= 0$

$\sf : \implies 33x + 47 = 0$

$\sf : \implies 33x = -47$

$\sf : \implies x = \dfrac{- 47}{33}$

Therefore, answer is $\sf x = \dfrac{- 47}{33}$

4 0

3 years ago

Read 2 more answers

Lia has 7 blue pencils and 28 red pencils. Maria has 14 blue pencils and 42 red pencils, and Tia has 10 blue pencils and 30 red

Sergeeva-Olga [200]

Maria and Tia have the same ratio

6 0

3 years ago

Read 2 more answers

What is this just tell me what the L AND W ='s please

andreyandreev [35.5K]

You didn't show us much of the page with the question on it,
so we can't be sure of exactly what you're working on in math.

If you're working with things like squares and rectangles, then
'L' and 'W' are often used to represent the Length and Width of
shapes drawn on paper, or even Length and Width of 3D objects
like blocks or boxes.

7 0

3 years ago

Read 2 more answers

huong and kathyrn each day impeoved their yards by planting rose bushes and ornamental grass. they bought their supplies from th

marta [7]

Answer:

One rose bush = $3

One bunch of ornamental grass = $4

Step-by-step explanation:

We can set up a system of equations to solve for this. Let cost of 1 rose bush be r and cost of 1 ornamental grass be g. Thus we can form 2 equations:

$14r+7g=70\\5r+14g=71$

We can multiply the first equation by -2 so that we can eliminate g. Thus, we have:

$(*-2)14r+7g=70\\5r+14g=71\\-------\\-28r-14g=-140\\5r+14g=71\\--------\\-23r=-69\\r=\frac{-69}{-23}=3$

Thus, 1 rose bush is $3. Now plugging in r = 3 into the first original equation, we can solve for g:

$14r+7g=70\\14(3)+7g=70\\42+7g=70\\7g=70-42\\7g=28\\g=\frac{28}{7}=4$

Thus, 1 bunch of ornamental grass is $4.

5 0

3 years ago