Tan(angle) = Opposite Leg / adjacent leg
tan(37) = x / 10
x = 10 *tan(37)
x = 7.5
Try, please, this:
1) Imagine, that pharmacist used 'x' gr. of 40% solution and 'y' of 70% solution.
Together (20 gr. of 52% sol.) it will be x+y=20.
2) From other side, the pharmacist combined 40x and 70y gramms, after obtaining together it is 52(x+y) gramms. In other words 40x+70y=52(x+y)
3)
Answer: 8 gr. of 70% solution and 12 gr. of 40%.
<h3>
<u>Answer:</u></h3>
52.38 inch² & 261.90 inch²
<h3>
<u>Step-by-step explanation:</u></h3>
Here we need to find the area of the sector . So according to formula we know the area of sector as ,
Here we can see that the central angle subtended by the arc is 60° and the radius of the circle is 10 inches . So the required area would be ,
=> Area = ∅/ 360° × π r²
=> Area = 60°/360° × 22/7 × (10in.)²
=> Area = 1/6 * 22/7 * 100 in²
=> Area = 52 .380 in²
<h3>
<u>★</u><u> </u><u>Hence </u><u>the </u><u>area </u><u>o</u><u>f </u><u>the </u><u>red</u><u> </u><u>sector </u><u>is </u><u>5</u><u>2</u><u>.</u><u>3</u><u>8</u><u> </u><u>inch²</u><u>.</u></h3>
<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>
Now let's find out the area of blue sector .The angle subtended by the arc will be (360-60)°=300° .
=> Area = 300/360 × 22/7 × 100 in²
=> Area = 261. 90 in²
<h3>
<u>★</u><u> </u><u>H</u><u>ence </u><u>the </u><u>area </u><u>of </u><u>blue </u><u>sector </u><u>is </u><u>2</u><u>6</u><u>1</u><u>.</u><u>9</u><u>0</u><u> </u><u>inch</u><u>²</u><u>.</u></h3>
Step-by-step explanation:
Given : AD=CD and
∠3=∠4
To prove : Line DB bisects ∠ABC
i.e.∠ABD=∠CBD
Proof : Consider ΔABD and ΔCBD,
and
and
So, ΔABD ≅ ΔCBD (By SAS criterion}
Hence , By CPCT (corresponding part of congruent triangle}
∠ABD=∠CBD
Therefore, Line DB bisects ∠ABC.
Answer:
i need more info to answer this
Step-by-step explanation: