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3 years ago

Find the equation of the linear function represented by the table below in slope-

Mathematics

2 answers:

Anarel [89]3 years ago

5 0

Answer:

y = 3x + 5

Step-by-step explanation:

slope:

11 - (-1) / 2 - (-2) = 12/4 = 3

slope intercept form is y = mx + b, so right now you have m = 3:

y = 3x + b

now, since you know x = -2 and y =-1 is a solution, you can plug those values in:

-1 = 3 * -2 + b

-1 = -6 + b

5 = b

This means the equation is y = 3x + 5

svp [43]3 years ago

5 0

Y=3x+5 should be it

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3 years ago

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marin [14]

Answer:

$P(x)=\dfrac{1}{1-x}+\dfrac{x^3}{(1-x)^2} \quad \text{for} \mid x \mid < 1$ [/tex]

Step-by-step explanation:

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$1,1,1,2,3,4,5,6,...$

the generating function would be

$P(x)=1+x+x^2+2x^3+3x^4+4x^5+5x^6+...\\$

we can multiply P(x) by x to get

$xP(x)=x+x^2+x^3+2x^4+3x^5+4x^6+...$

Note that

$P(x)-xP(x)=1+(2x^3-x^3)+(3x^4-2x^4)+(4x^5-3x^5)+(5x^6-4x^6)+...\\ \\=1+x^3+x^4+x^5+x^6+...=1+x^3(1+x+x^2+x^3+x^4+...)$

which for $\mid x \mid < 1$ can be rewritten as

$(1-x)P(x)=1+\dfrac{x^3}{(1-x)} \quad \Rightarrow \\\\P(x)=\dfrac{1}{(1-x)}+\dfrac{x^3}{(1-x)^2}$

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