8*40 = 320 * 2 = $640 for the 2 workers
640/2000 = 0.32
labor cost is 32% of the revenue
Answer:
to the first one the answer is 0. To the number 2 the answer is 2
Answer:
All real numbers is the answer
Step-by-step explanation:
Answer:
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Step-by-step explanation:
The area of a sphere is given by the following formula:

In which A is the area, measured in cm², and r is the radius, measured in cm.
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.
This means that 
Determine the rate of change in surface area when r = 20 cm.
This is
when
. So

Applying implicit differentiation.
We have two variables, A and r, so:



The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.