4 that’s the answer I think
Answer:
x = 3, and y = 2
Step-by-step explanation:
2x + 3y = 12 -------- (1)
y = x - 1 ---------------(2)
Substitute value of Y in (2) in (1)
2x + 3(x-1) = 12
2x + 3x - 3 = 12
5x - 3 = 12
5x = 12 + 3
5x = 15
x = 15/5
x = 3
Put the value of x in equation 2
y = x-1
y = 3 - 1
y = 2
Therefore, x = 3, and y = 2
Hope u understand
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Thank You
Answer:
$1916.667
Step-by-step explanation:
$46,000 / (12 months * 2) = $1916.667
What do you mean by "solve this?" Until you set f(x) = to some constant number, you don't have an equation and thus can't expect to find solutions.
Why don't we take <span>3x^2-18x+27 and set it = to 0, and only then try to solve this equation?
</span><span>3x^2-18x+27 = 0. Dividing both sides by 3, we get x^2 - 6x + 9= 0, which can be factored as
(x-3)^2 = 0. Taking the sqrt of both sides, we get x-3 = 0. Actually, there are 2 roots: 3 and 3. Again, this statement is true only if we set </span><span>3x^2-18x+27 = to 0.</span>
