Answer:
Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18
Step-by-step explanation:
Answer:
Good 4 U
Step-by-step explanation:
By Olivia Rodrigo
Answer: (b+5)(b-5)
Step-by-step explanation:
both b^2 and 25 are square numbers, so square root both of them to give b and 5, then put into brackets with a + and -
Answer:
-0.55 + 0.53a
Step-by-step explanation:
-0.55 – 0.47a + a
To find an expression equivalent to this, we must simplify the equation to a reasonable extent;
-0.55 – 0.47a + a
= -0.55 + 0.53a
= 0.53a - 0.55
The expression equivalent to the given one is -0.55 + 0.53a or 0.53a - 0.55
is proved
<h3><u>
Solution:</u></h3>
Given that,
------- (1)
First we will simplify the LHS and then compare it with RHS
------ (2)
Substitute this in eqn (2)
On simplification we get,
Cancelling the common terms (sinx + cosx)
We know secant is inverse of cosine
Thus L.H.S = R.H.S
Hence proved
