Answer:
true
Step-by-step explanation:
(2x 6)(x-1)=0 happy to help :)
Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
The answer is: [A]: " 2 × 3 × 5 × 7 " .
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210 = 70 * 3 ;
70 * 3 = 35 * 2 * 3 ;
35* 2* 3 = 7 * 5 * 2 * 3 ; which corresponds to "Answer choice: [A]." .
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That is where the line crosses the x axis or where y=0
0=-16x^2+22x+3
we gon do grouping
ac method
-16 times 3=-48
what 2 numbers multiply to get -48 and add to get 22
-2 and 24
0=-16x^2-2x+24x+3
group
0=(-16x^2-2x)+(24x+3)
undistribute
0=-2x(8x+1)+3(8x+1)
undistribute
0=(8x+1)(-2x+3)
set eaqual to 0
8x+1=0
8x=-1
x=-1/8
-2x+3=0
3=2x
3/2=x
x intercepts ate x=-1/8 and x=3/2
