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zvonat [6]
3 years ago
9

Ryan has 3/4 cup of pudding. How many 1/6 cup serving of pudding can ryan make?

Mathematics
1 answer:
ale4655 [162]3 years ago
4 0

You need to divide the amount he has by the serving size.

(3/4) / (1/6) =

= 3/4 * 6/1

= 18/4

= 4 1/2

He can make 4 1/2 servings.

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My son has the following missing number pattern to solve.
melisa1 [442]
The only complete pattern is the middle one
we see that 38-29=9
so the middle number minus the first number equals the third number
for the last row
21-1=20  so you have 1  21   20
for the first one

17- ?=37
54-17=37      54  17  37 
6 0
3 years ago
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What is the length of the altitude of the equilateral triangle below?​
ElenaW [278]

Answer:

A

Step-by-step explanation:

the height a creates with half of the baseline (5) and a leg (10) a right-angled triangle, and we can use Pythagoras to calculate a.

c² = a² + b²

c being the Hypotenuse (the side opposite of the 90° angle, so in our case the 10 side).

10² = a² + 5²

100 = a² + 25

75 = a²

a = sqrt(75) = sqrt(3×25) = 5×sqrt(3)

5 0
2 years ago
Find the volume of the composite solid 3 in. 8 in. 11 in.​
krok68 [10]
Answer is 264
You just multiply at three numbers
5 0
2 years ago
Please look at the included picture, show me your work and please include a good explanation. It would really help me out here.
Jobisdone [24]

These are indeed equivalent, and this identity is one of DeMorgan's laws.

The 6th column is the negation of the 5th column. For example, the first row says

not <em>p</em> or <em>q</em>

is true (T), so the negation would be false (F). The 5th column reads {T, F, T, T}, so the next column should be {F, T, F, F}.

Then in the 7th/last column, you are checking the truth value of the statement

<em>p</em> and not <em>q</em>

For example, in the first row, both <em>p</em> and <em>q</em> are true (T). This means (not <em>q</em>) is false, so (<em>p</em> and not <em>q</em>) is false (F). The last column should end up reading {F, T, F, F}, same as the previous column.

8 0
3 years ago
An airplane climbs 100 feet during the first second after takeoff. In each succeeding second it climbs 100 feet more than it cli
tigry1 [53]

Answer:

15 seconds.

Step-by-step explanation:

∵ The distance covered by plane in first second = 100 ft,

Also, in each succeeding second it climbs 100 feet more than it climbed during the previous second,

So, distance covered in second second = 200,

In third second = 300,

In fourth second = 400,

............, so on....

Thus, the total distance covered by plane in n seconds = 100 + 200 + 300 +400......... upto n seconds

=\frac{n}{2}(2\times 100 + (n-1)100)  ( Sum of AP )

=\frac{n}{2}(200+100n-100)

=\frac{n}{2}(100+100n)

=50n+50n^2

Suppose the distance covered in n seconds is 12,000 feet,

\implies 50n+50n^2=12000

n+n^2=240

n^2+n-240=0

n^2+16n-15n-240=0

n(n+16)-15(n+16)=0

(n-15)(n+16)=0

\implies n=15\text{ or }n=-16

∵ n can not be negative,

Hence, after 15 seconds the plane will reach an altitude of 12,000 feet above its takeoff height.

6 0
3 years ago
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