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nadezda [96]
3 years ago
8

Please help me solve this problem. ​

Mathematics
2 answers:
schepotkina [342]3 years ago
5 0

Answer:

Step-by-step explanation:

There is no solution

beks73 [17]3 years ago
3 0

Answer: There is no such value of X.

Step-by-step explanation:

If you get this wrong, im sorry but im sure that its the right answer.

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Find the value of x and y. To the nearest tenth.
Arturiano [62]

Answer:

x= 18.5 y = 14.2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Plz help i need answer.
In-s [12.5K]

Answer:

C

Step-by-step explanation:

Make a system of equations.

Justin = j

Greg = g

j + 15 = g

g/2 + 75 = j

We can substitute.

(j + 15)/2 + 75 = j

j/2 + 15/2 + 75 = j

j/2 = 165/2

j = 165

Substitute back into j + 15 = g

165 + 15 = g

g = 180

5 0
4 years ago
there are two identical glasses. one glass is 5/6 full. the other is 3/4 full. water is poured from one glass to the other so th
goldenfox [79]

Answer:

1 7/12

Step-by-step explanation:

because the water was poured to the other glass so it means that we are adding

= 5/6 + 3/4

={(2×5) + (3×3)}/12

that 12 is due to LCM of 6 and 4

={ 10 + 9 }/12

= 19/12

= 1 7/12

those are my thoughts

5 0
4 years ago
You have 3 dogs and they are playful. You decide that dogs are playful.
nadya68 [22]

Answer:

inductive

Step-by-step explanation:

3 0
3 years ago
In a multiple choice quiz, there are 5 questions each with 4 answer choices (a, b, c, and d). Robin has not studied for the quiz
k0ka [10]

Answer:

A.  0.1035

B.  0.1406

C.  0.1025

Step-by-step explanation:

Given that:

the number of sample questions (n) = 5

The probability of choosing the correct choice (p) = 1/4 = 0.25

Suppose X represents the number of question that are guessed correctly.

Then, the required probability that she gets the majority of her question correctly is:

P(X>2) = P(X=3) + P(X =4) + P(X = 5)

P(X>2) =  [ (^{5}C_{3}) \times (0.25)^3 (1-0.25)^{5-3} + (^{5}C_{4}) \times (0.25)^4 (1-0.25)^{5-4} + (^{5}C_{5}) \times (0.25)^5 (1-0.25)^{5-5}

P(X>2) = \Bigg [ \dfrac{5!}{3!(5-3)!} \times (0.25)^3 (1-0.25)^{2} + \dfrac{5!}{4!(5-4)!}  \times (0.25)^4 (1-0.25)^{1} +\dfrac{5!}{5!(5-5)!}  \times (0.25)^5 (1-0.25)^{0} \Bigg ]

P(X>2) = [ 0.0879 + 0.0146 + 0.001 ]

P(X>2) = 0.1035

B.

Recall that

n = 5 and p = 0.25

The probability that the first Q. she gets right is the third question can be computed as:

P(X=x) = 0.25 ( 1- 025) ^{x-1}

Since, x = 3

P(X = 3) = 0.25 ( 1- 0.25 ) ^{3-1}

P(X =3) = 0.25 (0.75)^{3-1}

P(X =3) = 0.25 (0.75)^{2}

P(X=3) = 0.1406

C.

The probability she gets exactly 3 or exactly 4 questions right is as follows:

P(X. 3 or 4) = P(X =3) + P(X =4)

P(X=3 \ or \ 4) =  [ (^{5}C_{3}) \times (0.25)^3 (1-0.25)^{5-3} + (^{5}C_{4}) \times (0.25)^4 (1-0.25)^{5-4}]

P(X=3 \ or \ 4) = \Bigg [ \dfrac{5!}{3!(5-3)!} \times (0.25)^3 (1-0.25)^{2} + \dfrac{5!}{4!(5-4)!}  \times (0.25)^4 (1-0.25)^{1} \Bigg ]

P(X = 3 or 4) = [ 0.0879 + 0.0146 ]

P(X=3 or 4) = 0.1025

3 0
3 years ago
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