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nadezda [96]
3 years ago
8

Please help me solve this problem. ​

Mathematics
2 answers:
schepotkina [342]3 years ago
5 0

Answer:

Step-by-step explanation:

There is no solution

beks73 [17]3 years ago
3 0

Answer: There is no such value of X.

Step-by-step explanation:

If you get this wrong, im sorry but im sure that its the right answer.

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Type the correct answer in each box. Use numerals instead of words. Solve the equation by completing the square. x2 + 20x + 82 =
VikaD [51]
7=x^2+20x+82
0=x^2+20x+75

What adds to 20 and multiplies to 75? 5 and 15.

x^2+5x+15x+75
x(x+5) 15(x+5)
(x+15) (x+5)

Zeroes are x= -5 and x= -15
5 0
3 years ago
Help with #5 please
slega [8]

729. multiple 9 times 9 then 81 times 9 and you get D

7 0
3 years ago
I need help pls I would appreciate it
KengaRu [80]
1.) D
2.) D
3.) C
4.) C
5.) 56 and 90 I looked for the pattern and followed it.
Get someone else to do 6 I cant
6 0
3 years ago
Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a
jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

6 0
3 years ago
SOMEONE HELPPPPPPPPP!!!!!!
Finger [1]

Answer:

104 yd^2.

Step-by-step explanation:

Area of the 2 circles = 2 * π r^2

=  2 * π * 4^2

= 32 π yd^2.

Area of the side of the cylinder = 2 π r h

= 2  π * 4 * 9

= 72 π yd^2.

Total surface area = 32 + 72

= 104 yd^2.

6 0
3 years ago
Read 2 more answers
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