We want to find the median for the given density curve.
The value of the median is 1.
Let's see how to solve this.
First, for a regular set {x₁, ..., xₙ} we define the median as the middle value. The difference between a set and a density curve is that the density curve is continuous, so getting the exact middle value can be harder.
Here, we have a constant density curve that goes from -1 to 3.
Because it is constant, the median will just be equal to the mean, thus the median is the average between the two extreme values.
Remember that the average between two numbers a and b is given by:
(a + b)/2
So we get:
m = (3 + (-1))/2 = 1
So we can conclude that the value of the median is 1, so the correct option is the second one, counting from the top.
If you want to learn more, you can read:
brainly.com/question/15857649
I think the answer is 156, I got this by multiplying 12 times 13.
The lateral area would be 298.7 cm².
The lateral area is the area of all of the lateral faces of the pyramid. There are 8 triangles making up the lateral faces. Each has a base of 6.6. The formula for the area of a triangle is
A=1/2bh,
so we still need the height of the triangle.
The height of each lateral triangle is the slant height of the pyramid. The slant height of the pyramid forms a right triangle with the height of the pyramid and the "radius" as it were of the pyramid. Thus we use the Pythagorean theorem:
8²+8²=h²
64+64=h²
128=h²
√128=√(h²)
8√2 = h
Substituting this into our area formula we have:
A=1/2(6.6)(8√2)
We will go ahead and multiply this by 8, since there are 8 lateral faces:
LA=8(1/2)(6.6)(8√2)
LA = 298.7
CONVENTIONAL LOAN. LIKE FHA AND VA
<span>In a jar of ten beads; since 3 are blue; probability of picking a blue ball, B, = p(b) = 3/10. And P (of not picking a blue ball) ; p(b') = 7/10.
Since it occurs with replacement, probabilities doesn't change
Probaility of picking k blue balls from on n attempts is given by P_n(k)
P_n(k) = (n, k) p^(k) q^(n -k) where p and q are b and b' respectively.
P_5(2) = (5 , 2) (0.3)^(2) (0.7)^(5 - 2)
P_5(2) = 5C2 (0.3)^(2) (0.7)^(3) = 0.3087</span>
