All categories

3 years ago

CONSUMER MATH!!

Mathematics

1 answer:

Alexxx [7]3 years ago

6 0

Answer:

$10.52

Step-by-step explanation:

(1137.45 x 14.7%) / 12 - (1137.45 x 3.6%) /12 = 10.52

You might be interested in

I need help. It's kinda hard for me. We have to use decimal numbers

cestrela7 [59]

Answer: 2.4 + 7.6 = 10

Step-by-step explanation:

Hope this helps

5 0

2 years ago

Find the value of x in the figure below 13x+8 2x+7

liberstina [14]

Step-by-step explanation:

step 1. (13x + 8) + (2x + 7) = 180 (definition of same side interior angles)

step 2. 15x + 15 = 180 (like terms)

step 3. 15x = 165 (subtract 15 from each side)

step 4. x = 11. (divide both sides by 15)

7 0

3 years ago

Ian is a phycologist interested in determining the proportion of algae samples from a local rivulet that belonged to a particula

pickupchik [31]

Answer: 16590

Step-by-step explanation:

The formula we use to find the sample size is given by :-

, where p = prior estimate of population proportion.

$z^*$ = Critical z-value (Two- tailed)

E= Margin of error .

Let p be the population proportion of cyanobacteria.

Given : E = 0.01

Critical value for 99% confidence interval : $z^*=2.576$

If Ian does not want to rely on previous knowledge , then we assume p=0.5 because the largest standard error is at p=0.5.

Now, the required sample size = $n=0.5(1-0.5)(\frac{2.576}{0.01})^2$

$n=0.25(257.6)^2=0.25(66357.76)=16589.44\approx16590$

Required sample size = 16590

5 0

2 years ago

The heights of dogs, in inches, in a city are normally distributed with a population standard deviation of 3 inches and an unkno

Nitella [24]

Answer: 1.2703

Step-by-step explanation:

Given : Sample size : n= 17, which is a small sample (n<30), so we use t-test.

Significance level : $\alpha:1-0.90=0.1$

Then , Critical value : $t_{n-1,\alpha/2}=t_{16, 0.05}\pm1.745884$

Standard deviation: $s=3\text{ inches}$

The formula to find the margin of error : -

$E=t_{n-1,\alpha/2}\dfrac{s}{\sqrt{n}}\\\\\Rightarrow\ E=(1.745884)\dfrac{3}{\sqrt{17}}\\\\\Rightarrow\ E=01.27031720154\approx1.2703$

Hence, the error bound (EBM) of the confidence interval with a 90% confidence level.=1.2703

6 0

3 years ago

The lifespan of a guinea pig is 6 years less than that of a giraffe. The lifespan of a tiger is 4 times that of the guinea pig.

faust18 [17]

Guinea pig (p) = 4 years old
Giraffe (g) = 10 years old
Tiger (t) = 16 years old

P = g-6
T = 4p

30 = g+g-6+(4(g-6))
30 = 2g-6+4g-24
30 = 6g-30
+30 +30
60 = 6g
6 6
10 = g

P = 10-6
P = 4

T = 4(4)
T = 16

8 0

2 years ago