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Leya [2.2K]
4 years ago
11

Please Help!!!!! The following set of numbers represents the number of hours a group of students spent reading over the course o

f two weeks.
3, 19, 11, 29, 4, 6, 10, 16, 2, 21, 15, 22, 13, 9, 1, 17, 2, 26, 18, 7
On your own sheet of paper, graph the set on a histogram, using six intervals in the display. Make sure to label your graph.

Mathematics
2 answers:
inessss [21]4 years ago
7 0

Find 6 intervals to use:

We can use 0-4, 5-9, 10-14, 15-19, 20-24 and 25-29

Then count the numbers from the list in each group:

0-4  there are 5 numbers in this group

5-9 there are 3

10-14 there are 3

15-19 there are 5

20-24 there are 2

25-29 there are 2


Now create the histogram, with the vertical axis labeled from 0 to 5 and the horizontal axis labeled with your six groups:

See attached picture:


Murljashka [212]4 years ago
3 0

Answer:

StepFind 6 intervals to use:

We can use 0-4, 5-9, 10-14, 15-19, 20-24 and 25-29

Then count the numbers from the list in each group:

0-4  there are 5 numbers in this group

5-9 there are 3

10-14 there are 3

15-19 there are 5

20-24 there are 2

25-29 there are 2

Now create the histogram, with the vertical axis labeled from 0 to 5 and the horizontal axis labeled with your six groups:

See attached picture:

Read more on Brainly.com - brainly.com/question/12099059#readmore-by-step explanation:

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3 years ago
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2x^2-4=124 is the correct answer.
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4 years ago
A right triangle has one angle that measure 23o. The adjacent leg measures 27.6 cm and the hypotenuse measures 30 cm.
MrMuchimi

Answer:

161.8cm²

Step-by-step explanation:

solve for height which is the opposite

opp=x

sin(theata)= opp./hyp.

sin23=x/30

x=30×sin23

x=11.72cm

height=opposite

height=11.72cm

base=adjacent

base=27.6cm

½of 27.6cm=13.8

13.8cm×11.72cm=161.74 (2d.p)

161.74 rounded to the nearest tenths= 161.7

I'm not sure if it's the answer but it's the closest thing to the options

4 0
3 years ago
Can anyone help me understand how to evaluate the limit of this complex fraction?
SSSSS [86.1K]

Answer:

-1/9

Step-by-step explanation:

\lim_{x \to 3} \frac{1/x-1/3}{x-3}

For simplicity, let's multiply top and bottom by 3x:

\lim_{x \to 3} \frac{3-x}{3x(x-3)}

Factor out a -1:

\lim_{x \to 3} \frac{-(x-3)}{3x(x-3)}

Divide top and bottom by x−3:

\lim_{x \to 3} \frac{-1}{3x}

Evaluate the limit:

\frac{-1}{3(3)}\\-\frac{1}{9}

It's important to note that the function doesn't exist at x = 3.  As x <em>approaches</em> 3, the function <em>approaches</em> -1/9.

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