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g100num [7]
3 years ago
5

Please help do these problems with work

Mathematics
1 answer:
choli [55]3 years ago
3 0
1st one #14 Is I think
y= -6x+11/2

2nd one #15 I think is
y=46-5x/7

3rdone#16 I think is
y=38-x/3

You might be interested in
In rhombus ABCD below, AC=30 cm and BD=18 cm. Find the area of the rhombus .I will give brainliest for the best and correct answ
barxatty [35]
Area of rhombus = 0.5 x D1 x D2

Thus,
Area = 0.5 x 30 x 18
= 270 units ^2
7 0
1 year ago
F [ x ] = [ x - 3] [ x + 8 ]
bogdanovich [222]

Answer:

f [ x ] = [ x - 3] [ x + 8 ] = x^2 + 5x - 24

Step-by-step explanation:

f (x)=[ x - 3] [ x + 8 ]

x [ x + 8 ] -3[ x + 8 ]

x^2 + 8x - 3x - 24

x^2 + 5x - 24

8 0
2 years ago
Find the set of values of k for which the line y=kx-4 intersects the curve y=x²-2x at 2 distinct points?
Sonbull [250]

Answer:

-6 < k < 2

Step-by-step explanation:

Given

y = x^2 - 2x

y =kx -4

Required

Possible values of k

The general quadratic equation is:

ax^2 + bx + c = 0

Subtract y = x^2 - 2x and y =kx -4

y - y = x^2 - 2x - kx +4

0 = x^2 - 2x - kx +4

Factorize:

0 = x^2 +x(-2 - k) +4

Rewrite as:

x^2 +x(-2 - k) +4=0

Compare the above equation to: ax^2 + bx + c = 0

a = 1

b= -2-k

c =4

For the equation to have two distinct solution, the following must be true:

b^2 - 4ac > 0

So, we have:

(-2-k)^2 -4*1*4>0

(-2-k)^2 -16>0

Expand

4 +4k+k^2-16>0

Rewrite as:

k^2 + 4k - 16 + 4 >0

k^2 + 4k - 12 >0

Expand

k^2 + 6k-2k - 12 >0

Factorize

k(k + 6)-2(k + 6) >0

Factor out k + 6

(k -2)(k + 6) >0

Split:

k -2 > 0 or k + 6> 0

So:

k > 2 or k > -6

To make the above inequality true, we set:

k < 2 or k >-6

So, the set of values of k is:

-6 < k < 2

3 0
2 years ago
What numbers are divisble by 23 but are between 2 and 10?
zloy xaker [14]
That is impossible.

For a number to be divisible by 23, it has to be greater than 23.

A number cannot be greater than 23, if you have restricted it to be within the numbers 2 and 10.
3 0
2 years ago
A small moving box has a volume of 2304 inches cubed and length of 16 inches. The box's width and height are the same. Write the
lisabon 2012 [21]

Answer:

<em>V = 16x² </em>

<em>Width = 12in</em>

<em>Height = 12in</em>

Step-by-step explanation:

Volume of the box is expressed as;

V = Length *Width * height

Given

Length = 16in

Width = x

Height = x

The volume of the box will be expressed as;

V = 16 * x * x

<em>V = 16x² (This gives the required equation)</em>

To get x:

We are given

V = 2304in³

Substitute;

2304 = 16x²

x² = 2304/16

x² = 144

x= √144

x = 12

<em>Hence the width and the height are both 12inches since they are the same.</em>

<em></em>

For the sma

8 0
3 years ago
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