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Kaylis [27]
2 years ago
7

I need help with this question7.035 ÷ 7 = ​

Mathematics
2 answers:
svp [43]2 years ago
6 0

Answer:

1.005

Step-by-step explanation:

Here you go this the answer

xxTIMURxx [149]2 years ago
6 0

Answer:

1.005 is the answer to your question

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Which equation is a function
suter [353]
The answer is A!! Hope I helped
5 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
erma4kov [3.2K]

Answer:

\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

Step-by-step explanation:

Given

5 tuples implies that:

n = 5

(h,i,j,k,m) implies that:

r = 5

Required

How many 5-tuples of integers (h, i, j, k,m) are there such thatn\ge h\ge i\ge j\ge k\ge m\ge 1

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed:  This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

^{n}C_r => ^{n + 4}C_5

^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}

^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}

Expand the numerator

^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

<u><em>Solved</em></u>

6 0
3 years ago
A cafeteria sells 30 drinks every 15 minutes. How many drinks can be sold in one hour?
aev [14]

Answer:30 drinks

Step-by-step explanation:

4 0
2 years ago
Which of the following is an equation of the line that crosses through (-3,4) and (3,6)?
Mama L [17]

Answer:

y=(1/3)x+5

Step-by-step explanation:

Slope-intercept: y=mx+b

m=((y2-y1)/(x2-x1)) = (6-4)/(3+3)= 2/6= (1/3)

y=(1/3)x+b

plug in one of the points (3,6)

6=(1/3)(3)+b

6=1+b    5=b

6 0
3 years ago
Select the equivalent expression
slava [35]
Answer: c
hope this helps!
7 0
3 years ago
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