Answer:
0.4
Step-by-step explanation:
Given:-
- The uniform distribution parameters are as follows:
a = $10,000 b = $15,000
Find:-
Suppose you bid $12,000. What is the probability that your bid will be accepted?
Solution:-
- We will denote a random variable X that defines the bid placed being accepted. The variable X follows a uniform distribution with parameters [a,b].
X ~ U(10,000 , 15,000)
- The probability of $12,000 bid being accepted can be determined by the cdf function of the uniform distribution, while the pmf is as follows:
Pmf = 1 / ( b - a )
Pmf = 1 / ( 15,000 - 10,000 )
Pmf = 1 / ( 5,000 )
D'(-3,-4)
E'(-3,-10)
F'(3,-6)
I think I may be missing something ... I don't completely understand your question.
All you need to make a fraction is two numbers and a bar. The bar can be either
horizontal or slanty. Then you write one number on top and the other number on
the bottom, and bada-bing, you have a fraction.
You can make fractions like
2700 / 600
27 / 6
9 / 2 (all 3 of these have the same value)
600 / 2700
6 / 27
2 / 9 (all 3 of these have the same value)
<span>The probability of missing the first shot is 40%.
When she misses the first shot, the probability of missing the second shot is very, very low, only 5%.
That means that the probability of missing both shots must be much smaller than the probability of missing the first shot.
40/100 * 5/100
0.4 * 0.05
= 0.02
= 2%</span>
(i) The area of the cross section ABCDEFG is 1771.6cm³
(ii) The volume of the concrete lab is 212592 cm³
(iii) the total surface area of the concrete slab is 30284 cm²
(iv) The mass of the concrete slab is 40746.8 kg/m³.
Given, dimensions are 120 cm by 60 cm by
40 cm.
(i) area of cross section = 40 × 60 ₋ π(60 ₋10 ₋ 10)/2 . 1/2
= 1771.6 cm³
(ii) the volume of the concrete slab = 40 × 60 × 120 ₋ 1/2 π((60 ₋ 10 ₋10)/2)² . 120
= 212592 cm³
(iii) The total surface area is:
=40 × 120 × 2 ₊ 60 × 120 ₊ 1771.6 × 2 ₊ 10 × 120 × 2 ₊ 1/2 π(60 ₋ 10 ₋10) × 120
= 30284 cm²
(iv) Mass of the concrete slab given density is 2300 kg/m³
Mass = Volume × density
Mass = 17.716 m³ × 2300
= 40746.8 kg/m³
Hence we get the mass as 40746.8 kg/m³.
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