Recall the definition of the cross product:
i x i = j x j = k x k = 0
i x j = k
j x k = i
k x i = j
The cross product is antisymmetric, or anticommutative, meaning that for any vectors u and v, we have u x v = - (v x u).
It's also distributive, so for any vectors u, v, and w, we have (u + v) x w = (u x w) + (v x w).
Taking all of these properties together, we get
b x a = (6i - j + 2k) x (2i + 2j - 5k)
b x a = 12 (i x i) - 2 (j x i) + 4 (k x i)
............. + 12 (i x j) - 2 (j x j) + 4 (k x j)
............. - 30 (i x k) + 5 (j x k) - 10 (k x k)
b x a = 1 (j x k) + 34 (k x i) + 14 (i x j)
b x a = i + 34j + 14k
Answer: idk the answer but i can tell u that u are trying to find the value of the symbols and the numbers :)
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Pythagorean Theorem: A^2 + B^2 = C^2
<span>We know A and C, let's find B by doing it backwards </span>
<span>C^2 - A^2 = B^2 </span>
<span>4^2 - 7 (square root of 7 squared is just 7) = B^2 </span>
<span>16 - 7 = B^2 </span>
<span>9 = B^2 </span>
