Know about the following topics. 1. Converse of Pythagorean Theorem. 2. 45-45-90 Right Triangles. 3. 30-60-90 Right Triangles. 4. Tangent Ratio. 5. Sine Ratio. 6. ... Check to see whether the side lengthssatisfy the equation c2. = a2 + b2. (√113)2 = 72 + 82. 113 = 49 + 64. 113 = 113 ✓. 7. 8. √113 ? ? The triangle is a.

5 0

3 years ago

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Is 10.10 greater than 10.01?

kolbaska11 [484]

Yes, it is 0.09 grater that 10.01

5 0

3 years ago

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Sin(60-theta)sin(60+theta)

ehidna [41]

Step-by-step explanation:

$\sin(60 - \theta) \sin(60 + \theta) \\ = \{ \sin(60) \cos( \theta) - \sin( \theta) \cos(60) \} \{ \sin(60) \cos( \theta) + \cos(60) \sin( \theta) \} \\ = \{ \frac{ \sqrt{3} }{2} \cos( \theta) - \frac{1}{2} \sin( \theta) \} \{ \frac{ \sqrt{3} }{2} \cos( \theta) + \frac{1}{2} \sin( \theta) \} \\ \\$

from difference of two squares:

${ \boxed{(a - b)(a + b) = ( {a}^{2} - {b}^{2} ) }}$

therefore:

$= \{ {( \frac{ \sqrt{3} }{2}) }^{2} { \cos }^{2} \theta \} - \{ {( \frac{ \sqrt{3} }{2} )}^{2} { \sin }^{2} \theta \} \\ \\ = \frac{3}{4} { \cos }^{2} \theta - \frac{3}{4} { \sin}^{2} \theta$

factorise out ¾ :

$= \frac{3}{4} ( { \cos }^{2} \theta - { \sin}^{2} \theta) \\ \\ = { \boxed{ \frac{3}{4} \cos(2 \theta) }}$

3 0

3 years ago

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Factor out 6x3 - 12x2 + 9x completely.

Radda [10]

Answer:

-3x x(2x²+4x-3)

Step-by-step explanation:

8 0

2 years ago