05/23727.90=100/x
105x=23727.90x100
105x=2372790
(105x)/105=2372790/105
x=22598
dealers cost is $22,598
<span>the 105% is the 100% price of the car plus the 5% of that tax</span>
Answer: he should invest $16129 today.
Step-by-step explanation:
Let $P represent the initial amount that should be invested today. It means that principal,
P = $P
It would be compounded annually. This means that it would be compounded once in a year. So
n = 1
The rate at which the principal would be compounded is 7.6%. So
r = 7.6/100 = 0.076
The duration of the investment would be 6 years. So
t = 6
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years.
A = 25000
Therefore
25000 = P(1+0.076/1)^1×6
25000 = P(1.076)^6
25000 = 1.55P
P = 25000/1.55
P = $16129
<span>52√+23√ = 4.79
Approx 5.1 is the answer.
Hope that helps. -UF aka Nadia
</span>
Answer:
- Part A: The price of fuel A is decreasing by 12% per month.
- Part B: Fuel A recorded a greater percentage change in price over the previous month.
Explanation:
<u>Part A:</u>
The function
calculates the price of fuel A each month by multiplying the price of the month before by 0.88.
Month price, f(x)
1 2.27 (0.88) = 1.9976 ≈ 2.00
2 2.27(0.88)² = 1.59808 ≈ 1.60
3 2.27(0.88)³ = 1.46063 ≈ 1.46
Then, the price of fuel A is decreasing.
The percentage per month is (1 - 0.88) × 100 = 12%, i.e. the price decreasing by 12% per month.
<u>Part B.</u>
<u>Table:</u>
m price, g(m)
1 3.44
2 3.30
3 3.17
4 3.04
To find if the function decreases with a constant ration divide each pair con consecutive prices:
- ratio = 3.30 / 3. 44 = 0.959 ≈ 0.96
- ratio = 3.17 / 3.30 = 0.960 ≈ 0.96
- ratio = 3.04 / 3.17 = 0.959 ≈ 0.96
Thus, the price of fuel B is decreasing by (1 - 0.96) × 100 =4%.
Hence, the fuel A recorded a greater percentage change in price over the previous month.
Answer:
$95.17
Step-by-step explanation:



