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2 years ago

Write two polynomials whose difference is 6x+3. Then prove it.

Mathematics

1 answer:

alexandr402 [8]2 years ago

6 0

Answer:

One possible pair:

7 x + 4 and x + 1

Step-by-step explanation:

There are infinitely many pairs that meet this requirement.

Please mark me brainliest :D

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How do u express one-half of the difference of a number cubed and one?

Ksivusya [100]

The expression ' one-half difference of a number cubed and one'. is written as \frac{1}{2}(x^3-1)

4 0

3 years ago

Please help me one more time

Vlad1618 [11]

Answer: 24

Yes (x-2) is a factor. There is a remainder.

Step-by-step explanation:

2³-8•2²+14•2-4

8-8•4+14•2-4

0•4+14•2-4

0+14•2-4

14•2-4

28-4

Hope this helps if so plz mark me brainly

5 0

3 years ago

This is what I need help with

siniylev [52]

The answer is 4

3 times 4 equals 12

A way to get the answer is by dividing 12 by 3 and you get 4 as well

4 0

3 years ago

Please help show work for part b it well help a lot and do part a too thanks

rjkz [21]

T=32+0.33c
b.t=32+0.33c
t=32+0.33(10)
t=32+(3.30)
t=35.30

7 0

3 years ago

Read 2 more answers

The volume of a soap bubble is 1,203.6 mm^3. Find the radius and diameter of the soap bubble. Use 3.14 for it.

madreJ [45]

The radius of the soap bubble=6.6 mm

The diameter of the soap bubble=13.2 mm

<u>Step-by-step explanation:</u>

The volume of the soap bubble is given in the problem and using this information we have to calculate its radius and diameter.

$volume=1203.6mm^3$

The soap bubble is in the shape of a sphere and we can use the equation of the volume of the sphere in this problem.

$volume=\frac{4}{3} \pi r^3\\1203.6=\frac{4}{3} \times 3.14\times r^3\\r^3=\frac{1203.6\times 3}{4\times3.14} \\r^3=287.48\\r=6.59 mm$

The radius of the soap bubble is 6.6 mm.

$diameter=2\times radius\\=2\times 6.6\\13.2 mm$

The diameter of the soap bubble is 13.2 mm

8 0

3 years ago