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devlian [24]
3 years ago
12

The perimeter of a pentagon is 48. One side is equal to x, two sides are twice x and two sides are three more than x. What are t

he measurements of the sides?
Mathematics
1 answer:
DochEvi [55]3 years ago
4 0

Answer:

  side lengths are 6, 12, 12, 9, 9

Step-by-step explanation:

The perimeter is the sum of the lengths of the sides:

  x + 2x + 2x + (x+3) + (x+3) = 48

  7x +6 = 48 . . . . collect terms

  7x = 42 . . . . . . .subtract 6

  x = 6 . . . . . . . . . divide by 7

Substitute this value into the expressions for the side lengths:

  x = 6

  2x = 12

  x+3 = 9

The side lengths are 6, 12, 12, 9, 9.

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Brrunno [24]
2 X { 6 + [ 12 divided ( 3 + 1 ) ] } - 1

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9 X 2 = 18

18 - 1 = 17!

17 is the answer

I used PEMDAS

P - Parenthesis

E - Exponents

M - Multiplication

D - Division

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S - Subtraction

[in order that your supposed to do]




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2 years ago
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mars1129 [50]

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