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Salsk061 [2.6K]
3 years ago
8

At the market 2.4 pounds of carrots cost $1.68 and 1.8 pounds of broccoli cost $1.53 how much more does 1 pound of broccoli cost

than 1 pound of carrots
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
5 0
Divided 1.68 by 2.4 = 0.7
1.53 divided by 1.8 = 0.85
0.85-0.7 = 0.15
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I will literally pay you pls help me :(
vovikov84 [41]

The answer is 35

Since they are supplementary they both equal 180 degrees.

(3x+10)+(2x-5)=180

Add them up

5x-5=180

Subtract 5 from both sides

5x=180-5

5x=175

Divide 5 from both sides

x=35.

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3 years ago
a manned rocket accelerates at a rate of 20 m/s2 during launch How long does it take the rocket reach a velocity of 400 m/s?
marshall27 [118]

Answer:

Step-by-step explanation:

acceleration, a = 20 m/s^2

initial velocity, u = 0 since it starts from rest

final velocity, v = 400 m/s

v = u + at

400 = 0 + 20 t

400 = 20 t

t = 400 / 20

<u><em>t = 20 sec</em></u>

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3 years ago
I've got a math test wish me luck​
kaheart [24]

Step-by-step explanation:

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6 0
2 years ago
On an airplane, there are two seats on the left side in each row and three seats on the right
pogonyaev

Answer:

a)64

b)96

Step-by-step explanation:

For this we calculate the number of rows, 32, as 2+3 is 5, and 160/5 is 32. Then we know that there are 32 rows, and in each row are 2 left seats and 3 right seats, so we multiply 32 by both numbers for the answers.  

3 0
2 years ago
Read 2 more answers
The annual rainfall (in inches) in a certain region is normally distributed with = 40 and = 4. What is the probability that star
sdas [7]

Answer:

0.93970

Step-by-step explanation:

Solution:-

- Denote a random variable "X" The annual rainfall (in inches) in a certain region . The random variable follows a normal distribution with parameters mean ( μ ) and standard deviation ( σ ) as follows:

                          X ~ Norm ( μ , σ^2 )

                          X ~ Norm ( 40 , 4^2 ).

- The probability that it rains more than 50 inches in that certain region is defined by:

                          P ( X > 50 )

- We will standardize our test value and compute the Z-score:

                          P ( Z > ( x - μ )  / σ )

Where, x : The test value

                          P (  Z > ( 50 - 40 )  / 4 )

                          P (  Z > 2.5 )

- Then use the Z-standardize tables for the following probability:

                          P ( Z < 2.5 ) = 0.0062

Therefore,          P ( X > 50 ) = 0.0062

- The probability that it rains in a certain region above 50 inches annually. is defined by:

                           q = 0.0062 ,

- The probability that it rains in a certain region rains below 50 inches annually. is defined by:

                           1 - q = 0.9938

                           n = 10 years   ..... Sample of n years taken

- The random variable "Y" follows binomial distribution for the number of years t it takes to rain over 50 inches.

                          Y ~ Bin ( 0.9938 , 0.0062 )

- The probability that it takes t = 10 years for it to rain:

                         =  10C10* ( 0.9938 )^10 * ( 0.0062 )^0

                         = ( 0.9938 )^10

                         = 0.93970

3 0
3 years ago
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