Question

NEED THIS SOLVED ASAP PLS HELP ME!!!

Answer 1

Answer:

x= 1 ±√21/3

x= 2.52753

x= - 0.527525

Step-by-step explanation:

-(-6) ±√-6² - 4 (3) (-4) / 2(3)

6±√36 -(-48) / 6

6±√84/6

6±2√21/6

6/6 ±2√21/6

1±√21/3

1+ √21/3 = 2.52753

1-√21/3= - 0.527525

Answer 2

Step-by-step explanation:

$3x ^{2} - 6x - 4 = 0$

$by \: quadratic \: formula$

$(-b±√(b²-4ac))/(2a)$

$- ( - 6)±√( - 6²-4(3)( - 4) /(2 \times 3)$

$(6±√(36 + 48)/(6)$

$(6±√(84)/(6)$

$(6±2√21)/6$

$2(3±√21)/6$

$3±√21/3$

$let \: \alpha \: and \: \beta \: be \: two \: roots \: .$

$3 + \sqrt{21} /3$

$3 + 4.58/3$

$7.48/3$

$2.52$

$and \: second \: root \: = 3 - \sqrt{21} /3$

$3 - 4.58/3$

$- 1.58/3$

$- 0.52$

$so \ \: alpha = 2.52 \: and \: \beta = - 0.52$