Answer:
C. m<XYA > m<ZYA.
Step-by-step explanation:
Since XY = YZ, as indicated in the information given, the angles opposite XY and YZ would also be of equal measure of degrees.
Thus, XA = 5. The angle opposite XA is m<XYA.
ZA = 3. The angle opposite ZA is m<ZYA.
Since XA > ZA, therefore,
m<XYA > m<ZYA.
Answer:
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that the selection of the random pages will contain at least two errors is 0.2644
Step-by-step explanation:
From the information given:
Let q represent the no of typographical errors.
Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let 
be the random variable that follows a Poisson distribution, then mean 
and the mean that the random selection of 50 pages will contain no error is 
∴
Pr(q =0) = 0.368
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that 50 randomly page contains at least 2 errors is computed as follows:
P(X ≥ 2) = 1 - P( X < 2)
P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2
![P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B%20%5Cdfrac%7Be%5E%7B-1%7D%201%5E0%7D%7B0%21%7D%20%2B%5Cdfrac%7Be%5E%7B-1%7D%201%5E1%7D%7B1%21%7D%20%5D)
![P(X \geq 2) = 1 - [0.3678 +0.3678]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B0.3678%20%2B0.3678%5D)
P(X ≥ 2) = 0.2644
The probability that the selection of the random pages will contain at least two errors is 0.2644
Alligators have a greater IQR because there were some very long alligators (high outliers)
Answer: x=3 y=3
Step-by-step explanation:
Assuming you meant 2x+3y=15 as the first problem. You have to make either both the x’s or both the y’all equal in both equations first. Multiply the second equation by 2 (for x’s) and you’ll get 2x+2y=12. The 2x cancels out so you’re left with 3y=15 and 2y=12. Subtract 2y=12 from 3y=15 and you get y=3.
Repeat to figure out x. Multiple second equation by 3 (for equal y’s) and you get 3x+3y=18. This time the first equation is being subtracted from the second one. (3x+3y=18) - (2x+3y=15). Y’s cancel out and you’re left with (3x=18)-(2x=15. Subtract and you get x=3
