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Alborosie
3 years ago
9

Cylinder A has a volume of 360 cm3. Cylinder B has a base and height identical to that of the cylinder B, but it is the right in

such a way that its slant length is greater by 4 cm. What is the volume of cylinder B?

Mathematics
1 answer:
Vladimir79 [104]3 years ago
7 0

<u>Answer:</u>

360 cm^{3}

<u>Step-by-step explanation:</u>

Here, one cylinder is right and the other cylinder is oblique or slanted.

In geometrical context, an object which is distorted so that it seems to lean over at a certain angle, in comparison to being completely upright is called an oblique object. While the right objects are exactly upright.

Since both the cylinders have the same base and height, so their volume is not affected by the lean of the cylinder B.

Therefore, cylinder B has the same volume as cylinder A i.e. 360 cm^{3}.

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7 0
3 years ago
Find the values of a and b such that x^2-2x+2=(x-a)^2+b
vekshin1

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6 0
3 years ago
Hat is the solution to the equation 3/3(4c + 16)=2c+9 ?<br><br> c =
marusya05 [52]
If it is \frac{3}{3(4c+16)}=2c+9, go to AAAAAA
if it is (\frac{3}{3})(4c+16)=2c+9, go to BBBBB

AAAAAAAAA
\frac{3}{3(4c+16)}=2c+9
\frac{1}{4c+16}=2c+9
times 4c+16 to both sides
1=(2c+9)(4c+16)
distribute
1=8c^2+68c+144
minus 1 both sides
0=8c^2+68c+143
use quadratic formula
c=\frac{-17- \sqrt{3} }{4} or \frac{-17+ \sqrt{3} }{4}




BBBBBBBBBBBB
(3/3)(4c+16)=2c+9
1(4c+16)=2c+9
4c+16=2c+9
minus 2c both sides
2c+16=9
minus 16 both sides
2c=-7
divide both sides by 2
c=-7/2
c=-3.5





if it is \frac{3}{3(4c+16)}=2c+9,
c=\frac{-17- \sqrt{3} }{4} or \frac{-17+ \sqrt{3} }{4}


if it is (\frac{3}{3})(4c+16)=2c+9, c=-3.5



7 0
3 years ago
Read 2 more answers
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