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zysi [14]
3 years ago
11

(2.5 x 10^-6) ÷ (5 x 10^-3)

Mathematics
1 answer:
sertanlavr [38]3 years ago
8 0
0.0000025 / 0.005 = 0.0005
=5 x 10^-4
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Write the 5th term in the expansion of (5x-y/2)^7
Nezavi [6.7K]

Answer:

65625/4(x^5)(y²)

Step-by-step explanation:

Using binomial expansion

Formula: (n k) (a^k)(b ^(n-k))

Where (n k) represents n combination of k (nCk)

From the question k = 5 (i.e. 5th term)

n = 7 (power of expression)

a = 5x

b = -y/2

....................

Solving nCk

n = 7

k = 5

nCk = 7C5

= 7!/(5!2!) ------ Expand Expression

=7 * 6 * 5! /(5! * 2*1)

= 7*6/2

= 21 ------

.........................

Solving (a^k) (b^(n-k))

a = 5x

b = -y/2

k = 5

n = 7

Substituting these values in the expression

(5x)^5 * (-y/2)^(7-5)

= (3125x^5) * (-y/2)²

= 3125x^5 * y²/4

= (3125x^5)(y²)/4

------------------------------------

Multiplying the two expression above

21 * (3125x^5)(y²)/4

= 65625/4(x^5)(y²)

5 0
3 years ago
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Answer:

10h and 48min

Step-by-step explanation:

60*18=1080

1080/100=10.8

so 10.8h which means 10 hours and 48 min

4 0
3 years ago
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Since 7 pages could be in 5 min.
So time required by 1 page 5/7 min.
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