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klemol [59]
3 years ago
11

Im not good with this. also letters should have never been added to math.

Mathematics
2 answers:
Sloan [31]3 years ago
5 0

Answer:

153

Step-by-step explanation:

bogdanovich [222]3 years ago
4 0

Answer: and explanation

multiply both sides of the equation by 3 to get:

3V = Bh      then divide both sides by h

h=3v/B

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Select the expressions that are equivalent to 8 2/3
user100 [1]
To change a mixed fraction, you'd multiply the number upfront, times the denominator, and then add that product to the numerator
that IS the new numerator, and you keep the denominator
thus \bf 8\frac{2}{3}\iff \cfrac{8\cdot 3+2}{3}
6 0
3 years ago
GCF of 28,42,and 56.<br><br> Please show work
natta225 [31]
<h2>Answer:  14</h2>

Step-by-step explanation:

If we factorize the numbers, we may be able to surmise the GCF:

28 = 2 × 2 × 7

42 = 2 × 3 × 7

56 = 2 × 2 × 2 × 7

∴ the GCF is 2 × 7 = 14

4 0
3 years ago
Come on plz tell me someone is awake
VladimirAG [237]

Answer:

I am

Step-by-step explanation:

1500

4 0
3 years ago
Read 2 more answers
Polygon A is similar to polygon B. The sides of polygon A are twice the length
mario62 [17]

Answer:

then the perimeter of polygon B will also be twice of perimeter of polygon A

8 0
3 years ago
Read 2 more answers
The length of a photograph is 3cm less than twice the width. The area is 54cm^2. Find the dimensions of the photograph.
REY [17]
W= width
l= length= 2w-3

Area= length * width
A= lw
substitute l=2w-3 for l
54= (2w-3)(w)
54= 2w^2 - 3w
subtract 54 from both sides
0= 2w^2 - 3w - 54
factor the polynomial
0= (2w + 9)(w - 6)

Set each set of parentheses equal
to 0 and solve for width.

0=2w+9
-9=2w
-4.5= w NEGATIVE VALUE

0=w-6
6 cm=w

-4.5 is not the answer because it has a negative value. You cannot have a negative side of a photograph. So substitute 6 in to find length.

length= 2w-3
l= 2(6)-3
l= 12-3
l= 9 cm

CHECK:
w= 6cm
l= 9cm
Area= length * width
54= 6*9
54= 54

ANSWER: width= 6cm; length= 9cm

Hope this helps! :)
4 0
3 years ago
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