Answer:

Step-by-step explanation:




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Answer: 294√3
Explanation:
1) The described hexagon has these featrues:
a) 6 congruent equilateral triangles whose side lengths measure 14
b) height of each triangle = apotema = a
c) the area of each triangle is base × a / 2 = 14 × a / 2 = 7a
2) a is one leg of a right triangle whose other leg is 14 / 2 = 7, and the hypotenuse is 14.
3) Then you can use Pythagorean theorem fo find a:
14² = 7² + a² ⇒ a² = 14² - 7² = 147 ⇒ a = √ 147 = 7√3
4) Therefore, the area of one triangle is: 14 × 7√3 / 2 = 49√3
5) And the area of the hexagon is 6 times that: 6 × 49√3 = 294√3
Answer:
idk I need the answer too
Step-by-step explanation:
:P
Obviously the smallest odd number we are looking for will have the SMALLEST four prime factors.
The smallest four prime numbers are 2,3,5,7. The lowest multiple of this is 2*3*5*7 = 210 But this is an even number!
So let's remove 2, and use the next prime number: 3,5,7,11. The lowest multiple of these is 3*5*7*11 = 1155.