<span>The
third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15))
</span>The solution would be like this
for this specific problem:</span>
<span>2^5 =
32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is
cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even
intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians.
</span>
<span>Roots
are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15
(or 7 pi /5 ).</span>
Answer:
x = – ⅓
Step-by-step explanation:
The solution to the expression can be obtained as follow:
–3.1x + 7 – 7.4x = 1.5x – 6(x – 3/2)
Clear bracket
–3.1x + 7 – 7.4x = 1.5x – 6x + 9
–3.1x – 7.4x + 7 = –4.5x + 9
–10.5x + 7 = –4.5x + 9
Collect like terms
–10.5x + 4.5x = 9 – 7
–6x = 2
Divide both side by –6
x = 2 / –6
x = – ⅓
Thus, the solution to the equation is –⅓
Answer:
11
Step-by-step explanation:
divide 209 by 19 to get an equal number of games each month (for 19 months), you will get 11 games each month.
3c(5+c) -2(3c-7)
15c+3c^2-6c+14
9c+3c^2+14
