Line a and line c are parallel lines that are given as a || c. Then the correct option is C.
<h3>How are parallel straight lines related?</h3>
Parallel lines have the same slope since the slope is like a measure of steepness and since parallel lines are of the same steepness, thus, are of the same slope.
Since the given parallel line has equation y = 2x + 2, thus its slope is 2 and thus, the slope of the needed line is 2 too.
Then we have
The distance between line a and line c is constant. Then line a and line c are parallel lines.
Line a || line c. Then the correct option is C.
Learn more about parallel lines here:
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<span> The triangle seems to be a scalene triangle because all three of its sides are different. </span>
Answer:
, ![\frac{5-\sqrt{17}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5-%5Csqrt%7B17%7D%7D%7B4%7D)
Step-by-step explanation:
One is asked to find the root of the following equation:
![2x^2+1=5x](https://tex.z-dn.net/?f=2x%5E2%2B1%3D5x)
Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:
![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
Change the given equation using inverse operations,
![2x^2+1=5x](https://tex.z-dn.net/?f=2x%5E2%2B1%3D5x)
![2x^2-5x+1=0](https://tex.z-dn.net/?f=2x%5E2-5x%2B1%3D0)
The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:
![\frac{-b(+-)\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%28%2B-%29%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,
![\frac{-b(+-)\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%28%2B-%29%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}](https://tex.z-dn.net/?f=%5Cfrac%7B-%28-5%29%28%2B-%29%5Csqrt%7B%28-5%29%5E2-4%282%29%281%29%7D%7D%7B2%282%29%7D)
Simplify,
![\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}](https://tex.z-dn.net/?f=%5Cfrac%7B-%28-5%29%28%2B-%29%5Csqrt%7B%28-5%29%5E2-4%282%29%281%29%7D%7D%7B2%282%29%7D)
![\frac{5(+-)\sqrt{25-8}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%28%2B-%29%5Csqrt%7B25-8%7D%7D%7B4%7D)
![\frac{5(+-)\sqrt{17}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%28%2B-%29%5Csqrt%7B17%7D%7D%7B4%7D)
Rewrite,
![\frac{5(+-)\sqrt{17}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%28%2B-%29%5Csqrt%7B17%7D%7D%7B4%7D)
, ![\frac{5-\sqrt{17}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5-%5Csqrt%7B17%7D%7D%7B4%7D)
Answer:
6(√2 - 5√3).
Step-by-step explanation:
3√2 ( 2 - 5 √6)
= 6√2 - 15√12
= 6√2 - 15√4√3
= 6√2 - 30√3
= 6(√2 - 5√3)