Question

First one right gets BRAINLIEST!! If f(x)=x²+2x-3 and g(x)=x²-9, find (f/g) 4 and (f+g)(4)

Answer 1

Answer:

3 and 28

Step-by-step explanation:

note ($\frac{f}{g}$ )(x ) = $\frac{f(x)}{g(x)}$

$\frac{f(x)}{g(x)}$

= $\frac{x^2+2x-3}{x^2-9}$  and

($\frac{f}{g}$ )(4) = $\frac{4^2+2(4)-3}{4^2-9}$ = $\frac{16+8-3}{16-9}$ = $\frac{21}{7}$ = 3

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(f + g)(x) = f(x) + g(x)

f(x) + g(x)

= x² + 2x - 3 + x² - 9 = 2x² + 2x - 12 and

(f + g)(4) = 2(4)² + 2(4) - 12 = 2(16) + 8 - 12 = 32 + 8 - 12 = 28