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Daniel [21]
2 years ago
14

Can any smart person out there help me with this homework ill pay you i just need it done

Mathematics
1 answer:
Ainat [17]2 years ago
8 0

Answer:

what is the question then???

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Two angels are supplementary. The measure of the large angle is four more than three times the measure of the small angle. Find
sashaice [31]

Answer:

The measure of the two supplementary angles is

Small angle = x = 44°

Large angle = y = 136

Step-by-step explanation:

Supplementary angles are two angles whose measures add up to 180° .

Let

Small angle = x

Large angle = y

x + y = 180°.... Equation 1

The measure of the large angle is four more than three times the measure of the small angle

Hence: y = 4 + 3x

We substitute 4 + 3x for y in Equation 1

x + 4 + 3x = 180°

4x + 4 = 180°

4x = 180° - 4

4x = 176

x = 176/4

x = 44°

Solve for y

y = 4 + 3x

y = 4 + 3(44)

y = 4 + 132

y = 136°

Therefore, the measure of the two supplementary angles is

Small angle = x = 44°

Large angle = y = 136

5 0
3 years ago
Choose the graph where the constant of variation is 2.
Rufina [12.5K]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
What is happening to this graph when the x-values are between 4 and 8?
Vilka [71]

Answer:

The correct answer is A. It is constant.

Step-by-step explanation:

When the x-values are between 4 and 8, this graph is constant.  This can be seen because the graph is a horizontal line, meaning it has zero slope.  Since the slope is zero, it is neither increasing nor decreasing, and is known as constant.

Hope this helps!

6 0
3 years ago
Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund
lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

\sigma=\sqrt{\frac{p*(1-p)}{n} }

If n=1139 and p =0.96, the standard deviation is:

\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836

The minimum and maximum usual values are:

\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n

\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62

5 0
3 years ago
Whoever gets this right, gets cake
Mariana [72]

Answer:

D is the answer

Step-by-step explanation:

don't froget my cake!! :)

5 0
2 years ago
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