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Daniel [21]
2 years ago
14

Can any smart person out there help me with this homework ill pay you i just need it done

Mathematics
1 answer:
Ainat [17]2 years ago
8 0

Answer:

what is the question then???

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lauren wants to keep her cell phone bull under $60 per month. Her current cell phone plan is $30 per month plus $0.50 per text.
stellarik [79]

Answer:

The correct answer is t < 60.

Step-by-step explanation:

Lauren wants to keep her cell phone bill below $60 per month.

Lauren's current cellphone plan charges her a fixed price of $30 and per text price for one text is $0.50.

Let Lauren sends t texts in a complete month.

Total money spent on texts in a month is given by $ (0.50 × t)

Therefore Lauren's total spent in a month is given by $ (30 + (0.50 × t)).

But this amount should be under $60 as per as the given problem.

∴ 30 + (0.50 × t) < 60

⇒ (0.50 × t) < 30

⇒ t < \frac{30}{0.50}

⇒ t < 60.

So in order to keep her phone monthly bill under $60, Lauren should keep her number of texts below 60.

8 0
3 years ago
In the equation, 7 (3a+12)=168 , what are some of the steps that should be taken to solve for x? Select all that apply.
Svetradugi [14.3K]

7(3a + 12) = 168 ← ( divide both sides by 7 )

3a + 12 = 24 ← ( subtract 12 from both sides )

3a = 12 ← ( divide both sides by 3 )

a = 4

OR

distribute the parenthesis by 7

21a + 84 = 168 ← ( subtract 84 from both sides )

21a = 84 ← ( divide both sides by 21 )

a = 4


5 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
Olin [163]

Answer:

Step-by-step explanation:

in tri ADC and tri BDC

∠ADC =∠BDC = 90

DC is common

AD = BD (given)

triangle ADC ≅ tri BDC by SAS congruency

hence AC = BC by CPCT ( congruent parts of congruent triangles)

hence, BC = 13

8 0
3 years ago
Read 2 more answers
What is the value of ?
Ede4ka [16]
Remember
\frac{x^m}{x^n}=x^{m-n}
and
x^{-m}=\frac{1}{x^m}

so
\frac{3^2}{3^4}=3^{2-4}=3^{-2}=\frac{1}{3^2}=\frac{1}{9}
5 0
4 years ago
The range of 16,23,55,64,49
miskamm [114]

Answer: 48

Step-by-step explanation: To find the range of the data set shown here, remember that the range is the difference between the greatest number in the data set and the least number in the data set.

<em>Greatest number</em> → 64

<em>Least number → </em>16

Now, we need to subtract 16 from 64.

64 - 16 = 48

Therefore, the range of the data set is 48.

7 0
3 years ago
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