Add up all the lengths of the garden and you will be able to get the perimeter.
Answer: He could have played more than 3 games.
Step-by-step explanation:
Hi, to answer this question we have to write an inequality.
I golf club charges $10 to join and $5 per game: So, the cost of playing golf is equal to $10 (joining price) plus the product of the number of games played (x) and the price per game (5).
That expression must be higher than 25, since john paid more than $25.
Mathematically speaking
10+ 5 x > 25
Solving for x
5x >25-10
5x >15
x >15/5
x> 3
He could have played more than 3 games, since his cost was higher ( not equal or higher) than 25.
2.5 *(10)+15=40
I guess this is the answer :)
Answer:
72 ads
Step-by-step explanation:
Let
x -----> the number of ads
we know that
5 sheets of construction paper for a title banner plus the number of ads multiplied by one quarter of sheet must be equal to 23 sheets of construction paper
so
The linear equation that represent this problem is

Solve for x
Multiply by 4 both sides to remove the fraction

Subtract 20 both sides


Answer:
3p³ + 2p² – 3p – 11
Step-by-step explanation:
From the question given above, the following data were obtained:
Side 1 (S₁) = –1(p + 5)
Side 2 (S₂) = 2(p² – 3)
Side 3 (S₃) = 3p³ – 2p
Perimeter (P) =?
The perimeter of the triangle can be obtained as follow
P = S₁ + S₂ + S₃
P = –1(p + 5) + 2(p² – 3) + 3p³ – 2p
Clear bracket
P = –p – 5 + 2p² – 6 + 3p³ – 2p
Rearrange
P = 3p³ + 2p² – 2p – p – 6 – 5
P = 3p³ + 2p² – 3p – 11
Therefore, the perimeter of the triangle is 3p³ + 2p² – 3p – 11