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Irina18 [472]
3 years ago
8

Help please now i cant figure it out

Mathematics
1 answer:
12345 [234]3 years ago
4 0

Answer:

a. \frac{-11}{24}

b. \frac{-3}{2} \\

c. \frac{31}{7}

d.  \frac{11}{16}

11, 3, 31, 11 = code

Step-by-step explanation:

a. \frac{-1}{6}\\ * 2\frac{3}{4} =

2\frac{3}{4} = \frac{4*2+3 }{4}=  \frac{11}{4}

\frac{-1}{6}\\ * \frac{11}{4} = \frac{-1*11}{6*4} = \frac{-11}{24}

b.  \frac{3}{16} / \frac{-1}{8} =

\frac{3}{16} * \frac{8}{-1} = \frac{3*8}{16*-1} \\ = \frac{24}{-16} = \frac{-3}{2} \\

c. \frac{-31}{56} * \frac{-8}{1} = \frac{31}{7} (you can reduce 8 & 56 by dividing by 8: 56/8=7 & -8/8= -1)

d. 1 \frac{7}{8} / 2\frac{8}{11} =

1 \frac{7}{8} = \frac{8*1+7}{8} = \frac{15}{8}

2\frac{8}{11} = \frac{11*2+8}{11} = \frac{30}{11}

\frac{15}{8} * \frac{11}{30} = \frac{11}{16} (you can reduce 15 & 30 by dividing by 15: 15/15=1 & 30/15 = 2)

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Then, the other leg = x + 3.

Ed will use the Pythagorean Theorem to find the hypotenuse.

So, let a = x one leg. Let b= x + 3 the other leg. And, let c = 15 the hypotenuse.

The Pythagorean Theorem is:

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We have:

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Hi!

Alright, so greater (or less) than or equal to is denoted with a bracket.

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Because x is <em>any</em> number under or equal to -4, x can range from negative infinity. However, we use a parentheses for infinity because infinity can never truly be reached.

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