Answer:
The length of the BC is 25 units .
Step-by-step explanation:
As shown in the diagram
In ΔABC
∠B = ∠C (As given)
(If the angles are equal than their opposite sides are also equal .)
Thus
AB = BC
As given
AB = 4x + 4
AC = 6x - 14
Thus
4x + 4 = 6x - 14
6x - 4x = 14 + 4
2x = 18

x = 9
Put in the
BC = 2x + 7
= 2 × 9 + 7
= 18 + 7
= 25 units
Therefore the length of the BC is 25 units .
Answer:
Step-by-step explanation:
Corresponding scores before and after taking the course form matched pairs.
The data for the test are the differences between the scores before and after taking the course.
μd = scores before taking the course minus scores before taking the course.
a) For the null hypothesis
H0: μd ≥ 0
For the alternative hypothesis
H1: μd < 0
b) We would assume a significance level of 0.05. The P-value from the test is 0.65. The p value is high. It increases the possibility of accepting the null hypothesis.
Since alpha, 0.05 < than the p value, 0.65, then we would fail to reject the null hypothesis. Therefore, it does not provide enough evidence that scores after the course are greater than the scores before the course.
c) The mean difference for the sample scores is greater than or equal to zero
Pretty sure it's 0, if you mean 2 to the power of 0
Answer:
X=-2
Y=-6
Step-by-step explanation:
Since both equations are already expressed in the simplest form of y, then we equate them to be equal hence
x-4=4x+2
Bringing like terms together
-4-2=4x-x
Solving both sides
-6=3x
Making x the subject then
X=-6/3=-2
Subsrituting the value of x into any of the initial equations
Y=x-4 then y=-2-4=-6
Therefore, the solution is
X=-2
Y=-6
Answer:
<h2>A)x=3/2 y=½</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
- system of linear equation
- PEMDAS
<h3>let's solve:</h3>
- since y is equal to both equation therefore we can substitute the value of y into the other equation




let's figure out y
- substitute the got value of x into the second equation: y=3*3/2 -4
- simplify multiplication:9/2 -4
- simplify division:4.5-4
- substract:0.5 alternate form:y=½