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nasty-shy [4]
3 years ago
6

Need answers for Question 8 and 9

Mathematics
2 answers:
Advocard [28]3 years ago
6 0

number 8 is C i think

il63 [147K]3 years ago
4 0
Question 8 is the number C
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Pls help me im confused
Artemon [7]

Answer:

c=36p+36

Step-by-step explanation:

Okay so the cost of the meal without tip is $36. To find the tip, we would multiply p by 36. To find our total (c), we would add this (36p) to the original 36.

In other words:

c=36p+36

(can also be written as c=36(1+p) )

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3 years ago
Twitter allows companies to reach consumers with
Travka [436]

Answer:

Short personal messages

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Rational numbers can be ______ or _______
chubhunter [2.5K]

Answer:

whole number or an integer.

Step-by-step explanation: hope this helps.

7 0
3 years ago
Can someone please help me with my maths question​
DIA [1.3K]

Answer:

a. \  \dfrac{625 \cdot m}{27 \cdot n^{11}}

b. \  \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}

By expanding the expression, we get;

\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}

Collecting like terms gives;

\dfrac{m^{(3 + 4 - 6)}  \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}

\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}

(b) The given expression is presented as follows;

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4

Therefore, we get;

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times  x^{-4} \times y^{-4 \cdot n}

Collecting like terms gives;

x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )

x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times  x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

4 0
3 years ago
Simplify the sum or difference of Square root 5+6 Square root 5
Alekssandra [29.7K]

200 is wrong because I just need to answer this question to finish my profile fully!

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3 years ago
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