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3 years ago

Bernie deposited $90 in a savings account earning 10% interest, compounded annually.

Mathematics

2 answers:

belka [17]3 years ago

7 0

Answer:

In three years Bernie total saving account would be $119.79

Step-by-step explanation:

The answer varies each year. In one year 10% of $90 is $9. Bernie total saving account would be $99 in the first year. In two years it would be $108.90( 10% of $99 = $9.9, $9.9 + $99 = $108.90). In three years Bernie total saving account would be $119.79( 10% of 108.90 = 10.89, $10.89 + $108.9 = $119.79) and so on.

VARVARA [1.3K]3 years ago

6 0

Answer:

$119.79

Step-by-step explanation:

im like 95% sure this is right

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

Consider the two data sets below:

alina1380 [7]

Answer:

Option c) The data sets will have the same values of their interquartile range.

Explanation:

1. The values are in order: they are in increasing oder, from lowest to highest value.

2. Calculate the interquartile range.

Interquartile range, IQR, is the third quartile, Q3, less the first quartile Q1:

IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

Data Set 1: 19, 25, 35, 38, 41, 49, 50, 52, 59

[19, 25, 35, 38], 41, [49, 50, 52, 59]

↑

median = 41

Data Set 2: 19, 25, 35, 38, 41, 49, 50, 52, 99

[19, 25, 35, 38] , 41, [49, 50, 52, 99]

↑

median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: First quartile

[19, 25, 35, 38],

↑

Q1 = [25 + 35] / 2 = 30

Third quartile

[49, 50, 52, 59]

↑

Q3 = [50 + 52] / 2 = 51

IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: First quartile

[19, 25, 35, 38]

↑

Q1 = [25 + 35] / 2= 30

Third quartile

[49, 50, 52, 99]

↑

Q3 = [52 + 50]/2 = 51

IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

An outlier will change the range because the range is the maximum value less the minimum value.

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3 years ago