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3 years ago

6

Eleven of the 25 people on the bus get off at the first stop. What percent best represents the portion of the bus that got off o

n the first stop?

1 answer:

Degger [83]3 years ago

6 0

Answer:

44%

Step-by-step explanation:

11 out of the 25 students got off the bus so we divide 11 by 25.

$\frac{11}{25} = .44$ .

$.44 = 44%$ %

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Can someone please tell me if i am right?

pentagon [3]

Second one is correct, that is an identity.

Third one is a contradiction:
6x - 15 = 3 * (2x - 6) ------> 6x - 15 = 6x - 18

Fourth one:
5x - 3 * (x - 4) = 2 * (x - 6) ---> 5x - 3x + 12 = 2x - 12 ---> 2x + 12 = 2x -12
So this is a contradiction as well.

4 0

3 years ago

Monica [59]

alligators:

x = total number of alligators

n = number of years

x=20x1.25^n

crocodiles:

y = total number of crocodiles

n = number of years

y=25+10n

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3 years ago

What do you think that ADA has explicit regulations on slopes and ramps?

yarga [219]

Answer:

I think that the ADA (Americans with Disabilities Act) has explicit regulations on slopes and ramps so that people with disabilities can go about their daily life easier, and to guarantee the safety and wellbeing of the disabled. If, for instance, a wheelchair ramp were too steep, there would be a danger of the wheelchair rolling down too quickly, or the person falling backward on their way up.

7 0

3 years ago

A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability

Hoochie [10]

Answer:

The probability of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

A city council consists of seven Democrats and five Republicans.
A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!\times (n-k)!}$

Compute the number of ways to select four people as follows:

${12\choose 4}=\frac{12!}{4!\times (12-4)!}=495$

Compute the number of ways to selected two Democrats as follows:

${7\choose 2}=\frac{7!}{2!\times (7-2)!}=21$

Compute the number of ways to selected two Republicans as follows:

${5\choose 2}=\frac{5!}{2!\times (5-2)!}=10$

Then the probability of selecting two Democrats and two Republicans as follows:

$P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242$

Thus, the probability of selecting two Democrats and two Republicans is 0.4242.

6 0

2 years ago

Step by step what is the answer to 11=12-q

Shtirlitz [24]

Your answer: q=1.

-

Steps:

1.) Add q to both sides. (11 + q = 12 - q + q.)

2.) Simplify. (11 + q = 12.)

3.) Subtract 11 from both sides. (11 + q - 11 = 12 - 11.)

4.) Simplify again. (q = 1.)

-

Hope this helped :)

7 0

3 years ago