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MakcuM [25]
1 year ago
14

Solve the system of equations by graphing. y = −5x y = x − 6 Part A Select the correct graph. A. Two lines graphed on a coordina

te plane. The decreasing line has Y intercept at zero and the increasing line has Y intercept at negative 6. The lines intersect at the point, 1, negative 5. B. Two lines graphed on a coordinate plane. The decreasing line has Y intercept at zero and the increasing line has Y intercept at 6. The lines intersect at the point, negative 1, 5. C. Two lines graphed on a coordinate plane. The decreasing line has Y intercept at negative 6 and the increasing line has Y intercept at 0. The lines intersect at the point, negative 1, negative 1. D. Two lines graphed on a coordinate plane. The decreasing line has Y intercept at 6 and the increasing line has Y intercept at 0. The lines intersect at the point, 1, 1. Part B Write the solution. 35 points!!!!
Mathematics
1 answer:
allochka39001 [22]1 year ago
3 0

(B) On a coordinate plane, two lines are graphed. The growing line's Y intercept is - 6, whereas the decreasing line's Y intercept is zero. the place where the lines converge ( 1, - 5).

Consider the system of equations,

y = - 5x and y = x - 6

To graph the equation y = - 5x we need to determine the points on the line.

When x = 0,

y = 0

When x = 1,

y = - 5

When x = 2.

y = - 5(2) = - 10

When x = - 1,

y = - 5( - 1 ) = 5

When x = - 2,

y = - 5 ( - 2 ) = 10

So, the point on the graph y = - 5x are ( 0, 0 ), ( 1, - 5 ), ( 2, - 10), ( - 1, 5 ), and ( - 2, 10 ).

Consider the equation,

y = x - 6

When x = 0,

y = - 6

When x = 1,

y = 1 - 6 = - 5

When x = 2,

y = 2 - 6 = - 4

When x = - 1,

y = - 1 - 6 = - 7

When x = - 2,

y = - 2 - 6 = - 8

So, the points are ( 0, - 6 ), ( 1, - 5 ), ( 2, - 4 ), ( - 1, - 7), and ( - 2, - 8).

So, the two lines intersect each other at ( 1, - 5 ).

The increasing line's y-intercept is at - 6 and the decreasing line's y-intercept is at 0.

Learn more about y-intercept here:

brainly.com/question/25722412

#SPJ9

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<u>Determining the value of y:</u>

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