Answer:
As per the statement:
A 25-foot ladder is placed against a building. The bottom of the ladder is 7 feet from the building.
⇒Length of the ladder against a building = 25 foot
and Length of the bottom of the ladder from the building= 7 feet.
You had Before the slip.
Let x be the height of the building where ladder hits the building
By Pythagoras theorem:
![\text{Hypotenuse side}^2=\text{Perpendicular}^2+\text{Base}^2](https://tex.z-dn.net/?f=%5Ctext%7BHypotenuse%20side%7D%5E2%3D%5Ctext%7BPerpendicular%7D%5E2%2B%5Ctext%7BBase%7D%5E2)
Here, Perpendicular side = Height of the building = x , Base = Length of the bottom of the ladder from the building = 7 foot and Hypotenuse side = 25 foot
Substitute the value to solve for x;
![25^2=x^2+7^2](https://tex.z-dn.net/?f=25%5E2%3Dx%5E2%2B7%5E2)
![625=x^2+49](https://tex.z-dn.net/?f=625%3Dx%5E2%2B49)
or
![x^2 = 625-49 = 576](https://tex.z-dn.net/?f=x%5E2%20%3D%20625-49%20%3D%20576)
foot.
⇒Height of the building = 24 foot
Now, if the ladder slips down 4 feet.
You had after slip
⇒Now, the height of the building becomes = 24-4 = 20 foot.
Let y be the distance from the building wall
then by Pythagoras theorem;
![y^2+20^2 = 25^2](https://tex.z-dn.net/?f=y%5E2%2B20%5E2%20%3D%2025%5E2)
![y^2+400 =625](https://tex.z-dn.net/?f=y%5E2%2B400%20%3D625)
![y^2 = 625-400 = 225](https://tex.z-dn.net/?f=y%5E2%20%3D%20625-400%20%3D%20225)
foot.
We have to find how many feet will the bottom slide out.
Since, Originally the distance of the bottom from the building = 7 foot
And now, the distance is = 15 foot.
The bottom slide out will be = 15 - 7 =8 foot
Therefore, 8 feet will the bottom slide out