Guys please help me with this question, I’d appreciate it a lot
1 answer:
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Answer:
x = 1, y = -2
Step-by-step explanation:
2x + 5y + 11 = 0 --- Equation 1
3x - y - 8 = 0
15x - 5y - 40 = 0 --- Equation 2
Equations 1+2: 2x + 5y + 11 + 15x - 5y - 40 = 0 + 0
17x - 29 = 0
17x = 29
x = 29 ÷ 17
x = 1
Substitute x = 1 into Equation 1:
2x + 5y + 11 = 0
2(1) + 5y + 11 = 0
3 + 5y = -11
5y = -11 - 3
= -14
y = -14 ÷ 5
y = -2
The <u>root</u> of the <u>function</u> is such point for which
The attached graph of the function shows, that the graph of the function intersects the x-axis in three points (2,0), (3,0) and (4.5,0).
This means that for
- x=2, f(2)=0;
- x=3, f(3)=0;
- x=4.5, f(4.5).
Thus, x=2, x=3 and x=4.5 are rational roots of the polynomial function f(x).
Answer: three rational roots.
