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vovangra [49]
3 years ago
13

The graph of f(x) = 2x3 – 19x2 + 57x – 54 is shown below. How many roots of f(x) are rational numbers

Mathematics
2 answers:
Luden [163]3 years ago
8 0

Answer:

3

Step-by-step explanation:

labwork [276]3 years ago
6 0

The <u>root</u> of the <u>function</u> is such point x_0, for which f(x_0)=0.

The attached graph of the function  f(x) = 2x^3 - 19x^2 + 57x - 54 shows, that the graph of the function intersects the x-axis in three points (2,0), (3,0) and (4.5,0).

This means that for

  • x=2, f(2)=0;
  • x=3, f(3)=0;
  • x=4.5, f(4.5).

Thus, x=2, x=3 and x=4.5 are rational roots of the polynomial function f(x).

Answer: three rational roots.

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If angle 1 = 6n + 1 and angle 4 = 4n + 19, what is the angle 2?
kobusy [5.1K]
Angles 1 and 4 are alternate angles and thus have the same measurement. You will set their equations equal to each other and solve for the variable. 

6n + 1 = 4n + 19

Subtract 1 and 4n from both sides to get variables on one side and constants on the other. 

6n - 4n = 19 - 1

Combine like terms and solve for n.

2n = 18
n = 18 / 2
n = 9

Angles 1 and 2 are congruent as labeled in the graph. 

So angle 2 is also 6n + 1

Plug in for 9 for n

6(9) + 1
54 + 1
55

Option C is your answer. 


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